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Sedaia [141]
3 years ago
11

Someone pls help with question 4

Physics
1 answer:
Alina [70]3 years ago
6 0

Answer:

given.. mass of copper 2kg

  • initial temperature is copper(I)=100°c
  • volume of water(5l)=5kg of water
  • initial water temperature =20°c
  • what's the final temperature(f)??

from the concept

heat lost from an object=heat gained by the other object

Heat=McΔT

Mč x Cč x ΔTč = Mw x Cw x ΔTw

2kg x 385J/kg°C x (100°c - {F}) = 5kg x 4200J/kg°C x ({f} - 20°C)

77000 - 770F = 21000F - 420,000

21770F =497000

....divide both sides....

F=22.83°C

therefore the final temperature of the water was 22.83°C

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<u>FOR HANDLE SIDE OF DOOR</u>:

τ₁ = F r₁

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<u>FOR MIDDLE OF DOOR</u>:

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