Answer:
The molar heat of vaporization of dichloromethane is 30.8kJ/mole
Explanation:
Using Clausius Clapeyron equation
ln (P1/P2) = (ΔHvap/R) (1/T2-1/T1)
At initial temperature of Ooc , the vapour pressure is 134mmHg
Therefore T1 = 0+273 =273K
And P1 = 134mmHg
At normal boiling point of 40oC , the vapour pressure is 760mmhg
T2 = 40 +273 = 313K
P2 = 760mmHg
ln (134/760) = ΔHvap/(8.3145 J/molK)
( 1/313K - 1/273K)
ΔHvap = 30800J/mol
= 30.8kJ/mol
Therefore, the molar heat of vaporization can be calculated using
Clausius Clapeyron equation using the above steps
Answer:
A
Explanation:
Since the new moon is behind the earth, It is sun, earth, moon
Answer:
1.44 atm
Explanation:
Step 1:
We'll begin by calculating the number of mole in 2,800,000 Liter of air.
I mole of air occupy 22.4L.
Therefore, Xmol of air will occupy 2800000L i.e
Xmol of air = 2800000/22.4
Xmol of air = 125000 moles
Step 2:
Determination of the pressure when the balloon is fully inflated .
This can be obtained as follow:
Number of mole (n) of air = 125000 moles
Volume (V) = 2800000 L
Temperature (T) = 120°C = 120°C + 273 = 393K
Gas constant (R) = 0.082atm.L/Kmol
Pressure (P) =.?
PV = nRT
Divide both side V
P= nRT/V
P= (125000x0.082x393) / 2800000
P = 1.44 atm
Therefore, the pressure of the air when the balloon is fully inflated is 1.44 atm
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