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zaharov [31]
3 years ago
13

How can you distinguish between a solution, colloid, and suspension?

Chemistry
1 answer:
RSB [31]3 years ago
3 0

Answer:

solution is clear solution while colloidal is between the solution and suspension. And in suspension particles are suspended.

Explanation:

In solution light can be passed without any scattering of light from solute particles while suspension is cloudy and having larger particle size than colloids, if suspension stands for a while particles will settle down easily.

In colloids light  will scattered and dispersed by reflecting with large particles.

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When optically active (R)-2-methylcyclohexanone is treated with either aqueous base or acid, racemization occurs. Explain.
IrinaK [193]

Answer:

See explanation

Explanation:

Racemization is said to occur when a 1:1 ratio of (+) and (-) enantiomers of a compound are produced in a reaction.

The reaction of optically active (R)-2-methylcyclohexanone with either aqueous base or acid leads to the formation of a planar enol species for reaction with acid and a planar enolate species for reaction with base.

Both reactions involves the formation of achiral species which reverts back to the chiral product with equal chances of the formation of both enantiomers of the product during the process. This leads to racemization of the product in both cases.

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Answer:

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A 2 kg bowlling ball is 2.5 meters off the ground on a post when it falls just before it reachers the ground it is traveling m/s
Alchen [17]
The mechanical energy is conserved 
Choice A
6 0
3 years ago
One process used to manufacture sulfuric acid is called the contact process...determine the amount of energy released when 1.00
Pepsi [2]
From the reaction; 

2SO2(g) + O2(g) = 2SO3(g)  + 394 kJ
   In the reaction a mixture of plantinum and vanadium (V) oxide may be used as a catalyst for the reaction. The sulfur trioxide produced is then used to make sulfuric acid.
 The energy that is required to release 1 mole of sulfur trioxide is +394 joules 
For one mole of sulfur trioxide; 
the energy that will be released will be 394/2 = 197 kJ
Thus; the amount of energy released is +197 kJ
5 0
3 years ago
A 10.000g ice cube is added to 100.000g of water at 80.0 oC in a calorimeter. The final temperature of the water in the calorime
Ket [755]

<u>Answer:</u> The amount of heat needed to melt the ice cube is 6.083 kJ

<u>Explanation:</u>

The processes involved in the given problem are:

1.)H_2O(s)(0^oC,273K)\rightarrow H_2O(l)(0^oC,273K)\\2.)H_2O(l)(0^oC,273K)\rightarrow H_2O(l)(65.5^oC,338.5K)

  • <u>For process 1:</u>

To calculate the amount of heat required to melt the ice at its melting point, we use the equation:

q_1=m\times \Delta H_{fusion}

where,

q_1 = amount of heat absorbed = ?

m = mass of ice = 10.000 g

\Delta H_{fusion} = enthalpy change for fusion = 334.16 J/g

Putting all the values in above equation, we get:

q_1=10.000g\times 334.16J/g=3341.6J

  • <u>For process 2:</u>

To calculate the heat required at different temperature, we use the equation:

q_2=mc\Delta T

where,

q_2 = heat absorbed

m = mass of ice = 10.000 g

c = specific heat capacity of water = 4.184 J/g.°C

\Delta T = change in temperature = T_2-T_1=[65.0-0]^oC=65.5^oC

Putting values in above equation, we get:

q_2=10.000g\times 4.184J/g.^oC\times 65.5^oC\\\\q_2=2741.83J

Total heat absorbed = q_1+q_2

Total heat absorbed = [3341.6+2741.83]J=6083.43J=6.083kJ

Hence, the amount of heat needed to melt the ice cube is 6.083 kJ

4 0
3 years ago
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