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Mekhanik [1.2K]
3 years ago
5

please help!!!!!! What is the mass of 1 mole of magnesium (Mg)? Express your answer to four significant figures. The mass of 1 m

ole of magnesium is _____ grams
Chemistry
2 answers:
Semmy [17]3 years ago
5 0
I believe you just look at your periodic table for this value. I don't think there is any math involved.
Therefore one mole of Mg = 24.305g.
andre [41]3 years ago
5 0

Answer: The mass of 1 mole of magnesium is 23.31  grams

Explanation:

Mass of magnesium = x

Molar mass of the magnesium = 24.31 g/mol

Moles = 1 mol=\frac{mass}{\text{Molar mass}}=\frac{x g}{23.31 g/mol}

Mass of the 1 mole of magnesium:

x=moles\times text{molar mass}=1 mol\times 23.31 g/mol= 23.31 g

The mass of 1 mole of magnesium is 23.31  grams

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Energy that comes from the heat of the Earth's core is known as geothermal energy.
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7 0
3 years ago
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Calculate the radius of a tantalum (ta) atom, given that ta has a bcc crystal structure, a d ensity of 16.6 g/cm3, and an atomic
Sidana [21]

solution:

Ta is BCC, a=\frac{4}{\sqrt{3}r},n=2atoms/cell\\p=16.6gram/cm^3,A=180.9gram/mol\\P=\frac{A\times n}{N_{a}\times v}=\frac{180.9\frac{gram}{mol}\times 2 \frac{atom}{cell}}{6.023\times10^23\frac{atom}{mol}\times(\frac{4}{\sqrt{3}\times r})^3\frac{cm^3}{cell}}\\=16.6\frac{gram}{cm^3}\\r=(\frac{180.9\times2}{16.6\times6.023\times10^23\times(\frac{4}{\sqrt{3}})^3})^\frac{1}{3}\times10^8


4 0
3 years ago
Q1.
dlinn [17]

Answer:

there are four peaks in the 13c NMR (B)

3 0
3 years ago
Which of the following is the number of moles of solute that is dissolved in 1 liter of solution?
Komok [63]
I believe the correct answer is option B. Molarity is the <span>number of moles of solute that is dissolved in 1 liter of solution. It is another way of expressing concentration of a mixture especially for solutions. Percent by mass is grams solute per grams of solution. Percent by volume is liter solute per liter per solution.</span>
4 0
3 years ago
How many grams of solid NaOH are required to prepare a 400ml of a 5N solution? show your work!
Nuetrik [128]

<u>Answer:</u> The mass of solid NaOH required is 80 g

<u>Explanation:</u>

Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

\text{Equivalent weight}=\frac{\text{Molecular weight}}{n}

where,

n = acidity for bases = 1 (For NaOH)

Molar mass of NaOH = 40 g/mol

Putting values in above equation, we get:

\text{Equivalent weight}=\frac{40g/mol}{1eq/mol}=40g/eq

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

\text{Normality of solution}=\frac{\text{Number of gram equivalents} \times 1000}{\text{Volume of solution (in mL)}}

Or,

\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}         ......(1)

We are given:

Given mass of NaOH = ?

Equivalent mass of NaOH = 40 g/eq

Volume of solution = 400 mL

Normality of solution = 5 eq/L

Putting values in equation 1, we get:

5eq/L=\frac{\text{Mass of NaOH}\times 1000}{40g/eq\times 400mL}\\\\\text{Mass of NaOH}=80g

Hence, the mass of solid NaOH required is 80 g

4 0
3 years ago
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