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Lyrx [107]
4 years ago
10

If the diffusion coefficient doubles, and the average diffusion distance across a membrane remains the same, what can be said ab

out the time it takes to cross the membrane g
Physics
1 answer:
Alex777 [14]4 years ago
6 0

Answer:

<u>time taken will be halved</u>

Explanation:

we have

t=\frac{x^{2}}{2D}   ..................(1)

where

t = time elapsed since diffusion began

x^{2} = mean distance traveled by the diffusion solute

D = Diffusion coefficient

now, according to the conditions given in the question

when, diffusion coefficient (D) doubles i.e D' = 2D

Average diffusion distance remains same i.e x' = x

substituting the values in the equation we get

t=\frac{x'^{2}}{2D'}

or

t=\frac{x^{2}}{2(2D)}

or

t=\frac{x^{2}}{4D} ...............(2)

hence, on comparing equation (1) and (2) we can say that the<u> time taken will be halved</u> when the diffusion coefficient doubles and the mean distance traveled remains the same

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You're having a hard time pushing a refrigerator across the kitchen floor. The force of your own push is 993 N. The force of fri
Helen [10]

Answer:

The acceleration of the refrigerator is a= 0.056 ms^{-2}

Explanation:

The expression of the equation of the net force acting on the refrigerator is as follows;

F-f= ma

Here, F is the applied force, f is the force of friction, m is the mass and a is the acceleration.

It is given in the problem that you're having a hard time pushing a refrigerator having mass 355 kg across the kitchen floor. The force of your own push is 993 N. The force of friction opposing your own push is 973 N.

Put F= 993, f= 973 N and m = 355 kg in the above expression of the equation to calculate the acceleration of the refrigerator.

993 - 973 = (355)a

20 = 355 a

a= 0.056 ms^{-2}

Therefore, the acceleration of the refrigerator is a= 0.056 ms^{-2}.

6 0
3 years ago
Bacteria vary somewhat in size, but a diameter of 2.9 μm is not unusual.
Sedbober [7]

Answer:

a) 6.4 x 10^-12 cm^3

b) 17 x 10^-6 mm^2

Explanation

a). The shape is assumed to be spherical The volume = volume of a sphere = \frac{4}{3} \pi r^3

3

4

πr

3

V = \frac{4}{3}*3.142* 1.15^3

3

4

∗3.142∗1.15

3

= 6.3715 μm^3

1 μm^3 = 10^-12 cm^3

6.3715 μm^3 = 6.3715 x 10^-12 cm^3

==> 6.4 x 10^-12 cm^3

8 0
2 years ago
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22. A 2.0 kg ball, traveling at 1.0 m/s, rolls off of a cliff of height 3.0 m. If the
RoseWind [281]

GOOD MORNING HAVE A NICE DAY

3 0
3 years ago
An isotropic point source emits light at wavelength 510 nm, at the rate of 170 W. A light detector is positioned 410 m from the
Wewaii [24]

Answer:

\frac{dB}{dt} = 3.03 \times 10^6 T/s

Explanation:

As we know that the power emitted by the source is given as

P = 170 W

now we know that

P = \frac{N}{t} (\frac{hc}{\lambda})

now we know that energy density is given as

u = \frac{B^2}{2\mu_0} + \frac{\epsilon_0 E^2}{2}

now we have

E = B c

u = \frac{B^2}{2\mu_0}

intensity is defined as

I = \frac{P}{A}

now we have

\frac{I}{c} = u = \frac{B^2}{2\mu_0}[/tex]

now we have

\frac{dB}{dt} = \omega B

\frac{dB}{dt} = \frac{2\pi c B}{\lambda}

\frac{dB}{dt} = \frac{2\pi c \sqrt{2\mu_0 I}}{\lambda\sqrt c}

here we have

I = \frac{P}{4\pi r^2}

I = \frac{170}{4\pi (410)^2}

I = 8.05 \times 10^{-5}

now we have

\frac{dB}{dt} = \frac{2\pi\sqrt{2\mu_0 c (8.05 \times 10^{-5})}}{(510 nm)}

\frac{dB}{dt} = 3.03 \times 10^6 T/s

4 0
3 years ago
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Lady bird [3.3K]

Explanation:

a chip on your shoulder is an example

6 0
3 years ago
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