Answer:
Time is 14.8 s and cannot landing
Explanation:
This is a kinematic exercise with constant acceleration, we assume that the acceleration of the jet to take off and landing are the same
Calculate the time to stop, where it has zero speed
Vf² = Vo² + a t
t = - Vo² / a
t = - 110²/(-7.42)
t = 14.8 s
This is the time it takes to stop the jet
Let's analyze the case of the landing at the small airport, let's look for the distance traveled to land, where the speed is zero
Vf² = Vo² + 2 to X
X = -Vo² / 2 a
X = -110² / 2 (-7.42)
X = 815.4 m
Since this distance is greater than the length of the runway, the jet cannot stop
Let's calculate the speed you should have to stop on a track of this size
Vo² = 2 a X
Vo = √ (2 7.42 800)
Vo = 109 m / s
It is conclusion the jet must lose some speed to land on this track
Answer:Train A is 90 m long and running at 72 km/h.
Train B is 120 m long and running at 36 km/h.
When the trains are running in opposite directions, their relative speed gets added: 72+36 = 108 km/h.
The total length of A and B = 90+120 = 210 m
So the time taken to cross each other = 210 m*60*60/108*1000m
= 7 seconds
Explanation:
Yes? I think a tutor would help with this!!!!
Electricity and Magnetism
