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1 year ago

Calculate the molarity of solution of "sodium sulfate" that contains 5.2 grams sodiums sulfate diluted to 500mL

1 answer:

3 0

Taking into account the definition of molarity, the molarity of solution of sodium sulfate is 0.0732 $\frac{moles}{liter}$ .

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

<h3>Molarity of solution of sodium sulfate.</h3>

In this case, you have:

number of moles of sodium sulfate= $5.2 grams\frac{1 mole}{142 grams} = 0.0366 moles$ (being 142 g/mole the molar mass of sodiums sulfate)
volume= 500 mL= 0.5 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

$Molarity=\frac{0.0366 moles}{0.5 L}$

Solving:

Molarity= 0.0732 $\frac{moles}{liter}$

Finally, the molarity of solution of sodium sulfate is 0.0732 $\frac{moles}{liter}$ .

Learn more about molarity:

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