Claire is investigating potential and kinetic energy using a large ball. For her investigation, Claire will stand at the top of
a hill and push the ball down the hill. The picture shows Claire's investigation
How will the ball's potential and kinetic energy change as it rolls down the hill?
Group of answer choices
The ball's potential energy will increase, and its kinetic energy will decrease.
The ball's potential energy will decrease, and its kinetic energy will increase.
The ball's potential and kinetic energy will both decrease.
The ball's potential and kinetic energy will both increase.
How will the ball's potential and kinetic energy change as it rolls down the hill?
Group of answer choices
The ball's potential energy will increase, and its kinetic energy will decrease.
The ball's potential energy will decrease, and its kinetic energy will increase.
The ball's potential and kinetic energy will both decrease.
The ball's potential and kinetic energy will both increase.
1 answer:
The ball's potential energy will decrease, and its kinetic energy will increase.
Explanation:
The ball's potential energy will decrease down the slope and its kinetic energy will increase.
Kinetic energy is the energy due to the motion of a body.
K. E = m v²
m is the mass of the ball
v is the velocity of the ball.
Potential energy is the energy due to the motion of a body down slope.
It is expressed as:
P.E = mgh
m is the mass of ball
g is the acceleration due to gravity of the body
h is the height.
We can see as the body drops down the slope, the height diminishes and the velocity increases.
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Answer:
The option closest to the percentage yield is option;
d. 81.1
Explanation:
The given chemical equation of the reaction is presented as follows;
CaO (s) + H₂O (l) → Ca(OH)₂
The mass of CaO in the experiment, m = 2.00 g
The volume of water with which the CaO was reacted = Excess volume of water
Number of moles = Mass/(Molar mass)
The mass of Ca(OH)₂ recovered, actual yield = 2.14 g
The molar mass of CaO = 56.0774 g/mol
The number of moles of CaO in the reaction, n₁ = 2.00 g/(56.0774 g/mol ≈ 0.036 moles
The molar mass of Ca(OH)₂ = 74.093 g/mol
The number of moles of Ca(OH)₂ in the reaction, n₂ = 2.14 g/(74.093 g/mol) ≈ 0.029 moles
From the given chemical reaction, one mole of CaO reacts with one mole of H₂O to produce one mole of Ca(OH)₂
Therefore, 0.036 moles of CaO will produce 0.036 moles of Ca(OH)₂
Mass = Number of moles × Molar mass
The mass of 0.036 moles of Ca(OH)₂ ≈ 0.036 moles × 74.093 g/mol = 2.667348 grams
∴ The theoretical yield of Ca(OH)₂ = 2.667348 grams
The percentage yield = (2.14 g)/(2.667348 grams) × 100 = 80.23%
Therefore, the option which is closest is option d. 81.1.