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o-na [289]
3 years ago
13

The ionization energy is the energy needed to remove an electron from an atom. In the bohr model of the hydrogen atom, this mean

s exciting the electron to the n = ∞ state. What is the ionization energy in kj/mol, for hydrogen atoms initially in the n = 2 energy level?
Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
6 0

The ionization energy for a hydrogen atom in the n = 2 state is 328 kJ·mol⁻¹.

The <em>first ionization energy</em> of hydrogen is 1312.0 kJ·mol⁻¹.

Thus, H atoms in the <em>n</em> = 1 state have an energy of -1312.0 kJ·mol⁻¹ and an energy of 0 when <em>n</em> = ∞.

According to Bohr, Eₙ = k/<em>n</em>².

If <em>n</em> = 1, E₁= k/1² = k = -1312.0 kJ·mol⁻¹.

If <em>n</em> = 2, E₂ = k/2² = k/4 = (-1312.0 kJ·mol⁻¹)/4 = -328 kJ·mol⁻¹

∴ The ionization energy from <em>n</em> = 2 is 328 kJ·mol⁻¹ .

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Answer:

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Identify what kind of ligand (weak or strong), what kind of wavelength (long or short), what kind of spin (high spin or low spin
anzhelika [568]

To find - Identify what kind of ligand (weak or strong), what kind

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2.

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3.

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