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2 years ago

Can anybody help me it says, Model the force that would cause each velocity change.

Physics

2 answers:

amid [387]2 years ago

8 0

Answer:

Explanation:

Please try to take a better photo as it is difficult to read.

For the first case, it is a small force to the right as there is a small velocity change.

For the second case, there is no force as there is no change in velocity

For the third case, it is a large (could be medium but photo is too blurry) force to the right as there is a large change in velocity.

kogti [31]2 years ago

5 0

Answer:

Explanation:

⇒ (small)

no force

<h2>⇒ (large)</h2>

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2 years ago

Trey races his bicycle for 192m. A wheel of his bicycle turns 48 times as the bicycle travels this distance. What is the diamete

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Answer:

1.27 m

Explanation:

Distance = 192 m

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Where, r be the radius of wheel.

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2 years ago

Read 2 more answers

The weight of a box is 1200 Newton if it exerts a pressure of 800 Pascal calculate the area

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Answer:

1.5m2

Explanation:

P=F/A. So here the force is given and the pressure is also given so you make the area the subject since that is what u are looking for

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2 years ago

A kicker kicks a ball off the ground at 29.5 mi/hr and at 42.5 degrees.

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2 years ago

A rocket car on a horizontal rail has an initial mass of 2500 kg and an additional fuel mass of 1000 kg. At time t0 the rocket m

slamgirl [31]

Answer: Acceleration of the car at time = 10 sec is 108 $m/s^{2}$ and velocity of the car at time t = 10 sec is 918.34 m/s.

Explanation:

The expression used will be as follows.

$M\frac{dv}{dt} = u\frac{dM}{dt}$

$\int_{t_{o}}^{t_{f}} \frac{dv}{dt} dt = u\int_{t_{o}}^{t_{f}} \frac{1}{M} \frac{dM}{dt} dt$

= $u\int_{M_{o}}^{M_{f}} \frac{dM}{M}$

$v_{f} - v_{o} = u ln \frac{M_{f}}{M_{o}}$

$v_{o} = 0$

As, $v_{f} = u ln (\frac{M_{f}}{M_{o}})$

u = -2900 m/s

$M_{f} = M_{o} - m \times t_{f}$

= $2500 kg + 1000 kg - 95 kg \times t_{f}s$

= $(3500 - 95t_{f})s$

$v_{f} = -2900 ln(\frac{3500 - 95 t_{f}}{3500}) m/s$

Also, we know that

a = $\frac{dv_{f}}{dt_{f}} = \frac{u}{M} \frac{dM}{dt}$

= $\frac{u}{3500 - 95 t} \times (-95) m/s^{2}$

= $\frac{95 \times 2900}{3500 - 95t} m/s^{2}$

At t = 10 sec,

$v_{f}$ = 918.34 m/s

and, a = 108 $m/s^{2}$

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2 years ago