Hey there!:
8) ΔTb = i*Kb*m
m is molality
Since same number of mol is added to same amount of water in both cases
m will be same for both
is 1 for glucose since it is covalent compound
is 4 of Al(NO3)3 as it breaks into 1 Al₃⁺ and 3 NO₃⁻
So, ΔTb will be 4 times in aluminum nitrate case
So, boiling point will change by 4ºC
9) use Q = m* L
L = heat of vaporization so:
T1=T2=100ºC
5.40 * 1000 => 5400 cal/g
Q = 5400 / 540
Q = 10 grams
Hope that thlps!
Since the water is at 100 degrees then it take 40.6 kj/mol to change 1 mole of water at 100 degrees into steam at 100 degrees
the moles of water 8.22mol
since one mole take 40.6kj/mol 8.22mol will be =
8.22mol x 40.6 kj/mol =333.732 kj
I Would Think that the answer is 55.845 u ± 0.002 u
Or you could just do<u> 55.85 Grams</u>
Evaporation and transpiration