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USPshnik [31]
3 years ago
6

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: CaO (s) + H 2O (l) → Ca(OH) 2 (s) In a p

articular experiment, a 2.00-g sample of CaO is reacted with excess water and 2.14 g of Ca(OH) 2 is recovered. What is the percent yield in this experiment?
Chemistry
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

The answer to your question is:  81%

Explanation:

Data

CaO = 2 g

Ca(OH)₂ = 2.14 g

Reaction balanced

                     CaO  +  H₂O   ⇒   Ca(OH)₂

                     

Molecular mass

Calcium oxyde = 40 + 16 = 56 g

Calcium hydroxide = 40 + 2 + 32 = 74 g

Process

Rule of three

                               56 g of CaO --------------   74 g of Ca(OH)₂

                                 2 g  of CaO -------------   x

                                 x = (2 x 74) / 56

                                x = 2.64 g of Ca(OH)₂

Percent yield

                         % Yield = \frac{2.14}{2.64}  x 100

                         % yield = 81                            

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Answer:

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3 years ago
A six-carbon organic compound containing oxygen is suspected of being either a secondary alcohol or a ketone. which chemical or
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6 0
3 years ago
Calculate the pOH of an aqueous solution of .0.073 M LiOH
Novosadov [1.4K]

Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).

pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.

LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:

[LiOH]= [OH-]= 0.073 M

Replacing in the definition of pOH:

pOH= -log (0.073 M)

<u><em>pOH= 1.14 </em></u>

In summary, the pOH of the aqueous solution is 1.14

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