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jok3333 [9.3K]
3 years ago
10

Mass is measured against a standard using a

Chemistry
2 answers:
Sholpan [36]3 years ago
6 0
The answer is c Balance hope it helps 
Tamiku [17]3 years ago
3 0
The answer is a balance
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What are the possible values of ml for l=2<br> ​
Marrrta [24]

Answer:

-2, -1, 0, 1, 2

Explanation:

There are four types of quantum numbers;

1) Principal quantum number (n)

2) Azimuthal quantum number (l)

3) magnetic quantum number (ml)

4) Spin quantum number (s)

The azimuthal quantum number (l) describes the orbital angular momentum and shape of an orbital while the magnetic quantum number shows the projections of the orbital angular momentum along a specified axis.  This implies that the magnetic quantum number shows the orientation of various orbitals along the Cartesian axes. The values of the magnetic quantum  number ranges from -l to + l

For l= 2, the possible values of the magnetic quantum number are; -2, -1, 0, 1, 2

5 0
3 years ago
How many electrons are in 1 mole of carbon atoms?
Mkey [24]

Answer:

6 electrons

Explanation:

7 0
3 years ago
Which graph correctly shows the effect on the freezing point caused by increasing the molality of a solution ?
beks73 [17]
The answer to your question is graph A :)
6 0
3 years ago
Read 2 more answers
A cube is 4 cm on each side. What is its volume?<br><br> Answer: 64cm^3
Anit [1.1K]

Answer:

yeah

Explanation:

5 0
3 years ago
What volume of 0.500 M HNO3(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?
asambeis [7]
KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol HNO3= 1 mol KOH (keep in mind this because it will be used later).

We also know that 0.100 M KOH aqueous solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the definition of molarity).

First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/ 1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.

Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.

The final answer is </span>(2) 20.0 mL.<span>

Also, this problem can also be done by using dimensional analysis. 

Hope this would help~ </span>
6 0
3 years ago
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