Given :
On a shelf sits a bottle of NaCl solutions with a molar concentration of 2.50 M and a total volume of 300 mL. If 15.0 mL of the solution is added to 985 mL of pure water .
To Find :
The molar concentration of NaCl in the new solution.
Solution :
Molarity M is given by :
Now , 1000 ml of NaCl contains 2.5 moles of NaCl .
So , 15 ml of NaCl contains :
New , volume V = 15 + 985 = 1000 ml = 1 L .
So , putting value of n and V in above equation :
Therefore , the molar concentration of NaCl in the new solution is 0.0375 M .
Hence , this is the required solution .
Here are the examples: It includes e.g. sunlight, wind, biomass, rain, tides, waves and geothermal heat.
Answer: 0.023 liters
Explanation:
Given that,
Original volume of gas (V1) = 25mL
[convert 25mL to liters
If 1000ml = 1L
25ml = 25/1000 = 0.025L]
Original temperature of gas (T1) = 22°C
[Convert 22°C to Kelvin by adding 273
22°C + 273 = 295K]
New volume of gas (V2) = ?
New temperature of gas (T2) = 0°C
[Convert 0°C to Kelvin by adding 273
0°C + 273 = 273K]
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
0.025L/295K = V2/273K
To get the value of V2, cross multiply
0.025L x 273K = 295K x V2
6.825L•K = 295K•V2
Divide both sides by 295K
6.825L•K/295K = 295K•V2/295K
0.023 L = V2
Thus, the new volume of the gas will be 0.023 litres
Answer:
Arsenic, As, has atomic number 33, which is the number of protons in the nuclei of its atoms. A neutral As atom would also have 33 electrons. The electron configuration of a neutral arsenic atom is [Ar]3d104s24p3
Explanation:
A. helium, neon and argon, because they are in the same group or column
