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Pie
3 years ago
11

To interconvert the concentration units molality (m) and mass percent, you must also know the density of the solution. A) True B

) False
Chemistry
1 answer:
uranmaximum [27]3 years ago
7 0

Answer:

The correct answer is option false.

Explanation:

Molality of the solution defined as moles of substance present in 1 kilogram of   solvent.

Moles = \frac{Mass of solute}}{\text{molar mass of solute}}

Molality=\frac{Moles}{\text{Mass of solvent(kg)}}

Mass of percent (w/w%) of the solution is defined as amount of solute present in 100 grams of solution.

(w/w\%)_=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

So, if want to inter-convert molality into mass percent we can do that without knowing density of solution.

Mass of solution = Mass of solute + Mass of solvent

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8. What is the name of this compound?
olga2289 [7]

Answer:

tert-butyl bromide

Explanation:

sec-butyl bromide

CH3 -CH-CH2-CH3

         Br

tert-butyl bromide

       CH3

CH3-C- Br

       CH3

isopropyl bromide

       CH3

CH3-CH-Br

isobutyl bromide

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6 0
3 years ago
3<br> Convert 5.492 x 104 grams to units of micrograms.<br> (Click to select 4<br> x 10<br> ug
Soloha48 [4]

Answer:

5.492*10^10

Explanation:

1g=1000000microgram

3 0
3 years ago
A student has 10 mL of a solution that might contain any or all of the following cations at 0.01 M concentrations: Mn2+, Ba2+, A
Ivanshal [37]
<span>For the answer to the question above,
Addition of HCl causes a precipitate to form: 
Ag+ & Cl- -- AgCl a white ppt 


H2SO4 is added to the supernate another precipitate forms: 
Ba+2 & SO4-2 --> BaSO4 a white ppt 


a solution of NaOH is added to the supernatant liquid until it is strongly alkaline. No precipitate is formed: 
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I hope this helps you.
7 0
3 years ago
The specific heat capacity of liquid water is 4.18 J/g oC. Calculate the quantity of energy required to heat 1.50 g of water fro
natima [27]

Answer: The quantity of heat required is 358.644 J.

Explanation:

Given: Specific heat capacity = 4.18 J/g^{o}C

Mass = 1.50 g

T_{1} = 26.5^{o}C

T_{2} = 83.7^{o}C

Formula used to calculate heat energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass

C = specific heat capacity

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 1.50 \times 4.18 J/g^{o}C \times (83.7 - 26.5)^{o}C\\= 358.644 J

Thus, we can conclude that quantity of heat required is 358.644 J.

5 0
3 years ago
Another way to say reactants is Question 4 options:
Alik [6]
<h2><em>Answer:</em></h2><h2><u><em>Compounds or  ingredients</em></u><em> I took the test and these are the only one's i didn't try so hope you have good luck and brainliest plz?</em></h2><h2><em>Explanation:</em></h2>

3 0
3 years ago
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