The (C4H1 0)3N represents a___ amine. A. Primary B. Secondary C. Tertiary
2 answers:
Answer :The correct answer for (C₄H₁₀ )₃ N is C) TERTIARY AMINE .
The substitution level of nitrogen in amine or in simple words , description of carbon atoms attached to a given nitrogen in any amine is of 4 types :
1 ) Primary amine :
When the given nitrogen is attached to only one carbon then substitution level is known as PRIMARY amine.
Example : CH₃NH₂ : The nitrogen is attached to only one carbon (CH₃) . Hence it is primary amine
2) Secondary amine :
When the given nitrogen is attached to two carbons .
Example : (CH₃)₂NH : The nitrogen is attached to two carbon ( CH₃)₂ , hence it is secondary amine .
3) Tertiary amine :
When the given nitrogen is attached to three carbon atom .
Example : (CH₃)₃NH : The nitrogen is attached to 3 carbons atoms (CH₃)₃ . Hence it is a tertiary amine
4) Quaternary amine : when the nitrogen attached to 4 carbon atoms and amine posses a positive charge on it , its is known as quaternary amine .
Example : (CH₃)₄N⁺ : The nitrogen is attached to 4 carbons and nitrogen . hence it is quaternary amine .
(Image attached )
The given compound is (C₄H₁₀ )₃ N has 3 groups of C₄H₁₀ attached to N , means 3 carbons attached to N , ( image attached ) . Hence it can be said that (C₄H₁₀ )₃ N is TERTIARY AMINE .
Hence correct option is C) Tertiary amine .
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<u>Answer:</u> The for the reaction is 72 kJ.
<u>Explanation:</u>
Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.
The given chemical reaction follows:
The intermediate balanced chemical reaction are:
(1)
(2)
( × 2)
(3)
( × 2)
The expression for enthalpy of the reaction follows:
Putting values in above equation, we get:
Hence, the for the reaction is 72 kJ.