The increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.
<h3>What is gravitational potential energy?</h3>
The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.
The potential energy increases by 3773 J
PE₂-PE₁=mg(h₂-h₁)
3773 J = 35.0 × 9.81 × (h₂-h₁)
(h₂-h₁) = 10.98
Case 2 ;
ΔPE =?
ΔPE=mg(h₂-h₁)
ΔPE=56.0 × 9.81 ×10.98
ΔPE=6031.97 J.
Hence, the increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.
To learn more about the gravitational potential energy, refer;
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Answer:
–735.17 N
The negative sign indicate that the force is acting in opposition direction to the car.
Explanation:
The following data were obtained from the question:
Mass (m) of car = 782.10 kg
Initial velocity (u) = 7.60 m/s
Final velocity (v) = 3.61 m/s
Time (t) = 4.23 s
Force (F) =?
Next, we shall determine the acceleration of the car. This can be obtained as follow:
Initial velocity (u) = 7.60 m/s
Final velocity (v) = 3.61 m/s
Time (t) = 4.23 s
Acceleration (a) =?
a = (v – u) / t
a = (3.61 – 7.60) / 4.23
a = –3.99 / 4.23
a = –0.94 m/s²
Finally, we shall determine the force experienced by the car as shown below:
Mass (m) of car = 782.10 kg
Acceleration (a) = –0.94 m/s²
Force (F) =?
F = ma
F = 782.10 × –0.94
F = –735.17 N
The negative sign indicate that the force is acting in opposition direction to the car.
You could probably expect normal plant growth, as a white light is similar to the sun in the respect that it contains all colors of the spectrum.
Answer: The electric field is: a) r<a , E0=; b) a<r<b E=ρ (r-a)/εo;
c) r>b E=ρ b (b-a)/r*εo
Explanation: In order to solve this problem we have to use the Gaussian law in diffrengios regions.
As we know,
∫E.dr= Qinside/εo
For r<a --->Qinside=0 then E=0
for a<r<b er have
E*2π*r*L= Q inside/εo in this case Qinside= ρ.Vol=ρ*2*π*r*(r-a)*L
E*2π*r*L =ρ*2*π*r* (r-a)*L/εo
E=ρ*(r-a)/εo
Finally for r>b
E*2π*r*L =ρ*2*π*b* (b-a)*L/εo
E=ρ*b* (b-a)*/r*εo
Answer:
all scenarios are using the same power
Explanation:
we know that power is defined as P(Watts)=W(Joules)/t(seconds).
When applying this formula to each of the scenarios we find:
Done
