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Vlad1618 [11]
3 years ago
9

How high does Pete lift his sledge hammer if he used a force of 25N to lift the hammer while doing 50J of work?

Physics
1 answer:
sasho [114]3 years ago
8 0

Answer:He lifts 2 meters

Explanation:We are trying to find the distance. The formula for distance is W/Force. 50 is our amount of work. 25N is how much force was used. Divide the work bye the force. 50/25=2M

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Assuming the average rate of heat energy flowing outwards from earth to be 0.063 W/m2 calculate the energy available at a hot sp
MaRussiya [10]

Answer:

"13.48 Kwhr" is the right solution.

Explanation:

The given values are:

Average rate of heat energy,

= 0.063 W/m²

Diameter,

= 8m

Efficiency of conversion,

= 50%

Now,

The area of hotspot will be:

⇒  A=\frac{\pi}{4} d^2

On substituting the values, we get

⇒      =\frac{3.14}{4} (8)^2

⇒      =0.785\times 64

⇒      =50.24 \ m^2

Total heat generation rate will be:

⇒  Q=q\times A

        =0.063\times 50.24

        =3.16 \ W

hence,

The electricity generation capacity will be:

⇒  P=\eta Q t

On substituting the values, we get

⇒      =0.5\times 3.16\times 8760

⇒      =13840.8 \ Whr

On converting into Kwhr, we get

⇒      =13.84 \ Kwhr

6 0
3 years ago
A particle is confined to a one-dimensional box that is 50 pm long. What is the smallest possible uncertainty in momentum for th
nevsk [136]

Answer:

The smallest possibility is 0.01E-22kgm/s

Explanation:

Using

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= 6.6x 10^-34Js/ 4(3.142* 50*10-12m)

= 0.01*10^-22kgm/s

6 0
3 years ago
What is the frequency of an event?
konstantin123 [22]

"Frequency" just means "often-ness" ... how often something happens.
It's always expressed as

        <em>(number of happenings) / (some period of time) .</em>


4 0
3 years ago
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sertanlavr [38]
V=(40km/hr)(hr/3600s)(1000000mm/km)
v=11111.1mm/s

v=d/t
d=vt
d=(11111.1mm/s)(5s)
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d=5.56x10^4mm
4 0
3 years ago
Use the galvanometers to determine the amount and direction of the induced current. Which galvanometer is
docker41 [41]

Answer:

Option B

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For galvanometer B, the reading is 4 mA.

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4 0
3 years ago
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