Answer:
"13.48 Kwhr" is the right solution.
Explanation:
The given values are:
Average rate of heat energy,
= 0.063 W/m²
Diameter,
= 8m
Efficiency of conversion,
= 50%
Now,
The area of hotspot will be:
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
Total heat generation rate will be:
⇒ 


hence,
The electricity generation capacity will be:
⇒ 
On substituting the values, we get
⇒ 
⇒ 
On converting into Kwhr, we get
⇒ 
Answer:
The smallest possibility is 0.01E-22kgm/s
Explanation:
Using
Momentum= h/4πx
= 6.6x 10^-34Js/ 4(3.142* 50*10-12m)
= 0.01*10^-22kgm/s
"Frequency" just means "often-ness" ... how often something happens.
It's always expressed as
<em>(number of happenings) / (some period of time) .</em>
V=(40km/hr)(hr/3600s)(1000000mm/km)
v=11111.1mm/s
v=d/t
d=vt
d=(11111.1mm/s)(5s)
d=55555mm
d=5.56x10^4mm
Answer:
Option B
Explanation:
Looking at the 3 galvanometer readings given above, for galvanometer A, the reading is -2 mA.
For galvanometer B, the reading is 4 mA.
While for galvanometer C, the reading is -5 MA
Thus, option B is correct.