Answer:
6.07 N
Explanation:
Given that,
Force, F = 35 N
It makes 10 degree angle with the positive x-axis.
We need to find the magnitude of the vertical component of the force. It can be given by :
So, the magnitude of the vertical component of the force is 6.07 N.
The answers include the following:
- The unit of length most suitable for measuring the thickness of a cell phone is a meter.
- The unit of length most suitable for measuring the height of a backyard tree is a meter.
<h3>What is Meter?</h3>
This is defined as the standard unit for measuring the length of a body and is denoted as m.
Height is a vertical type of length which is why meter was chosen as the most appropriate choice.
Read more about Meter here brainly.com/question/1578784
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Answer:
As an object’s temperature increases, the Rate at which it radiates energy increases.
If the period of a satellite is T=24 h = 86400 s that means it is in geostationary orbit around Earth. That means that the force of gravity Fg and the centripetal force Fcp are equal:
Fg=Fcp
m*g=m*(v²/R),
where m is mass, v is the velocity of the satelite and R is the height of the satellite and g=G*(M/r²), where G=6.67*10^-11 m³ kg⁻¹ s⁻², M is the mass of the Earth and r is the distance from the satellite.
Masses cancel out and we have:
G*(M/r²)=v²/R, R=r so:
G*(M/r)=v²
r=G*(M/v²), since v=ωr it means v²=ω²r² and we plug it in,
r=G*(M/ω²r²),
r³=G*(M/ω²), ω=2π/T, it means ω²=4π²/T² and we plug that in:
r³=G*(M/(4π²/T²)), and finally we take the third root to get r:
r=∛{(G*M*T²)/(4π²)}=4.226*10^7 m= 42 260 km which is the height of a geostationary satellite.
