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tatuchka [14]
3 years ago
13

An experiment measures the growth of crystals in a liquid solution abroad the space shuttle a collection of bottles has the liqu

id in varying strength or concentration of this tested substance what she would be a control observation in this experiment
Physics
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

Explanation:

Protein crystals growth where first performed on space lab.

Experiment show that the liquid to liquid space grown system are larger than crystals obtained by same experiment on earth.

Crystallization in the microgravity experiment in space can be controlled and it will improve crystal quality by eliminating convection effects near growing crystal surfaces.

Diffraction in the microgravity experiment in space can also be controlled and it will also improve the quality attributed to better ordered crystal growth in microgravity.

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What is the outermost structure in a plant cell
dybincka [34]
Molecular structure of the primary cell wall in plants. Up to three strata or layers may be found in plant cell walls: The middle lamella, a layer rich in pectins. This outermost layer forms the interface between adjacent plant cells and glues them together.
5 0
3 years ago
How does energy from an earthquake reach each surface? Describe the three types of seismic waves.
WITCHER [35]
Body waves travel through the interior of the Earth. Surface waves travel across the surface. Surface waves decay more slowly with distance than body waves which travel in three dimensions. Particle motion of surface waves is larger than that of body waves, so surface waves tend to cause more damage.
https://en.m.wikipedia.org › wiki
4 0
3 years ago
A spring with a constant k=400n/m shoots a 1. 00kg ball up a frictionless incline after being compressed 0. 150m. what is the ma
Zielflug [23.3K]

The maximum height reached by the ball is 0.46m.

To find the answer, we have to know about the potential energy of a spring mass system.

<h3>How to find the maximum height reached by the ball?</h3>
  • It is given that,

                       k=400N/m\\m=1kg\\x=0.150m\\h=?\\

  • We have to find the maximum height reached by the ball.
  • Thus, we have the expression for potential energy of a spring mass system and that of gravitational field as,

                             U=\frac{1}{2}kx^2 \\U=mgh

  • Combining both, we get,

                    h=\frac{kx^2}{2mg} =\frac{400*(0.15)^2}{2*1*9.8} =0.46m

Thus, we can conclude that, the maximum height reached by the ball is 0.46m.

Learn more about the potential energy here:

brainly.com/question/26962934

#SPJ4

8 0
1 year ago
If a car is taveling with a speed 6 and comes to a curve in a flat road with radius ???? 13.5 m, what is the minumum value the c
Lemur [1.5K]

Answer:

\mu_s \geq 0.27

Explanation:

The centripetal force acting on the car must be equal to mv²/R, where m is the mass of the car, v its speed and R the radius of the curve. Since the only force acting on the car that is in the direction of the center of the circle is the frictional force, we have by the Newton's Second Law:

f_s=\frac{mv^{2}}{R}

But we know that:

f_s\leq \mu_s N

And the normal force is given by the sum of the forces in the vertical direction:

N-mg=0 \implies N=mg

Finally, we have:

f_s=\frac{mv^{2}}{R}  \leq \mu_s mg\\\\\implies \mu_s\geq \frac{v^{2}}{gR}  \\\\\mu_s\geq \frac{(6\frac{m}{s}) ^{2}}{(9.8\frac{m}{s^{2}})(13.5m) }\\\\\mu_s\geq0.27

So, the minimum value for the coefficient of friction is 0.27.

4 0
3 years ago
When landing after a spectacular somersault, a 45.0 kg gymnast decelerates by pushing straight down on the mat. Calculate the fo
STALIN [3.7K]
So the force that the gymnast with a mass m=45 kg, has to exert against the ground to stop if her acceleration is a=8*g, where g=9.81 m/s², can be obtained from the Newtons second law: F=m*a, where F is the force, m is the mass and a is acceleration. 

F=m*a=m*8*g=45*8*9.81=3531.6 N. 

So the force that a gymnast has to exert on the mat in order to stop is F=3531.6 N.  
6 0
3 years ago
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