Atomic radius decreases and electronegativity
increases in order of increasing atomic number
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Lewis structure for each of the following N₂O₃ with no N¬N bond is attached below.
Even though pi symmetry occupies the antibonding orbitals of NO, this is unimportant after the dimer forms. A sigma connection exists. The enthalpy of the newly formed sigma bond in the dimer is low because the loss of a particularly distinctive set of single-electron resonance forms that were available for no monomer offset the net gain in bond. When the whole free energy is taken into account, there is no gain because the entropic effects are on the order of 1030kJ/mol, and dimerization is entropically disfavored at G=17kJ/mol. Therefore, any little increase in enthalpy is cancelled out by the loss of entropy.
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<u>Answer:</u> The number of atoms of bromine present in given number of mass is
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of bromine = 1.37 g
Molar mass of bromine = 79.904 g/mol
Putting values in above equation, we get:
According to mole concept:
1 mole of an element contains number of atoms.
So, 0.0171 moles of bromine will contain = number of bromine atoms.
Hence, the number of atoms of bromine present in given number of mass is
Answer:
The reactant here is sucrose. It is the substance that decompose into carbon dioxide and water. Sucrose is the one who undergoes a chemical change in the process therefore it is the reactant. Carbon dioxide and water on the other hand are the products of the reaction.
Answer:the reaction in which two water molecules produce ions is called self-ionization of water
For example
H2O➡️H+ +OH-
Explanation: