Responder: A.) 24.5m / s B.) 30.625m C.) 89.375m
Explicación:
Dado lo siguiente:
Altura desde la cual se cae el cuerpo = 120 m
Tiempo (t) = 2.5s
A.) La velocidad que toma:
El cuerpo cayó desde una altura;
velocidad inicial (u) = 0
Para calcular v:
V = u + en
Donde a = aceleración debido a la gravedad = 9.8m / s
v = 0 + (9.8) (2.5)
v = 24.5 m / s
B) Cuánto ha disminuido.
Usando la ecuación de movimiento:
S = ut + 0.5at ^ 2
Donde S = distancia
S = 0 × 2.5 + 0.5 (9.8) (2.5 ^ 2)
S = 0 + 0.5 (9.8) (6.25)
S = 30.625 m
Esta es la distancia recorrida después de 2.5 segundos Altura o distancia ha disminuido en 30.625 m
C.) ¿CUÁNTO FALTA? Por lo tanto, 120m - 30.625m = 89.375m
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