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Ainat [17]
3 years ago
5

How many atoms of oxygen are in a molecule of glucose?​

Chemistry
2 answers:
m_a_m_a [10]3 years ago
6 0
The answer is 6. it's made up of 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms.
Ivanshal [37]3 years ago
5 0

Answer:

6 oxygen atoms

Explanation:

For example – glucose (C6H12O6), a common sugar molecule, is made up of 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.

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Difference between sodium ion and sodium atom.<br>(give in points not in paragraph)​
Natali5045456 [20]

Answer:

Explanation:

SODIUM ATOM;

SODIUM ATOM IS NEUTRAL

SODIUM ION;

IT IS A CHARGED SPECIE WITH A CHARGE OF +1

SODIUM ATOM:

THE NUMBER OF PROTONS AND ELECTRONS ARE SAME ie:11

SODIUM ION:

NUMBER OF PROTONS AND ELECTRONS ARE NOT SAME ie. ELETRON: 10, PROTONS:11

HOPE IT WILL HELP:)

3 0
2 years ago
What are two factors that determine an object's gravitational potential energy?
Vesna [10]
Weight and Height... 
3 0
3 years ago
Read 2 more answers
In a reaction, gaseous reactants form a liquid product. The heat absorbed by the surroundings is 1.1 MJ, and the work done on th
ratelena [41]

Answer: \Delta E is 1155 kJ

Explanation:

According to first law of thermodynamics:

\Delta E=q+w

\Delta E=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=-P\Delta V  {Work done on the system is positive as the final volume is lesser than initial volume}

w =13.2kcal=55.2kJ   (1kcal=4.184 kJ)

q = +1.1 MJ = 1100 kJ  (1MJ=1000kJ)   {Heat absorbed by the system is positive}

\Delta E=1100kJ+(55.2)kJ=1155kJ

Thus \Delta E is 1155 kJ

4 0
3 years ago
What is the maximum magnification of a compound light microscope?
igor_vitrenko [27]

Answer: 100x

Explanation:

The actual power or magnification of a compound optical microscope is the product of the powers of the ocular (eyepiece) and the objective lens. The maximum normal magnifications of the ocular and objective are 10× and 100× respectively, giving a final magnification of 1,000×.

8 0
3 years ago
Read 2 more answers
15. A 15.30 g sample of calcium (Ca) combines with 7.96 g of sulfur(S) to form calcium sulfide
BlackZzzverrR [31]

Answer:

17.689g

Explanation:

1: First, write out the equation you will follow:

Ca + S ⇒ CaS

2: Use the formula Mass = Mr x moles to work out the moles of both Ca and S - this will enable you to find the limiting reactant.

3: Moles Ca:

Moles = mass/ Mr = 15.3/ 40.1 = 0.382 moles.

4: Moles S:

Moles = mass/ Mr = 7.96/ 32.1 = 0.245 moles.

5: We now know S is the limiting reactant, and as there is a 1:1 ratio between S and CaS, there will also be 0.245 moles CaS.

6: Mass CaS:

Mass = Mr x moles = 72.2 x 0.245 = 17.689g

6 0
3 years ago
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