Question

A 4.00-kg block of ice is placed against a horizontal

Answer 1

Answer:

a) 0.0625

b) 0.177 m/s

Explanation:

The spring has potential energy stored, when it pushes on the ice block it will use that energy to perform work. The work will be converted into kinetic energy on the ice block.

The elastic potential energy on the spring is:

Ep = 1/2 * k * Δx^2

Ep = 1/2 * 200 * 0.025^2 = 0.0625 J

That is the energy that will be transferred as kinetic energy on the ice block.

Ec = 1/2 * m * v^2

Rearranging:

v^2 = 2 * Ec / m

$v = \sqrt{ 2 * Ec / m}$

$v = \sqrt{ 2 *0.0625 / 4} = 0.177 m/s$