Yes because something that has been electrically charged can make other things move without touching them ( this is called force without contact)
Hoped this helped :)
25 km/hr I hope this helps;)
Answer:
Explanation:
Using the atomic mass of pluonium atoms (244 g/mol), you can calculate the number of atoms in 47.0 g. Then, knowing that each plutonium atom has 96 protons, you calculate the number of protons in the 47.0 g sample. Finally, using the positive charge of one proton, you calculate the total positive charge in the 47.0 g of plutonium.
<u>1. Number of atoms of plutonium in 47.0 g</u>
- Number of moles = mass / atomic mass = 47.0 g / 244 = 0.1926 moles
- Number of atoms = number of moles × 6.022 × 10²³ atoms/mol
- Number of atoms = 0.1926 mol × 6.022 × 10²³ atoms/mol = 1.15998×10²³ atoms
<u>2. Number of protons</u>
- Number of protons = 1.15998×10²³ atoms × 96 protons/atom = 1.11385×10²⁵ protons
<u>3. Charge</u>
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- Charge = charge of one proton × number of protons
- Charge = 1.602×10⁻¹⁹ C/proton × 1.11385×10²⁵ protons = 1.78×10⁶C
Answer:
20 seconds.
Explanation:
The following data were obtained from the question:
Distance = 10 m
Speed = 0.5 m/s
Time =...?
The speed of an object is simply defined as the distance travelled by the object per unit time. Mathematically, it is expressed as:
Speed = Distance /time
With the above formula, we can obtain the time taken for the ball to travel a distance of 10 m as shown below:
Distance = 10 m
Speed = 0.5 m/s
Time =...?
Speed = Distance /time
0.5 = 10/time
Cross multiply
0.5 × time = 10
Divide both side by 0.5
Time = 10/0.5
Time = 20 secs.
Therefore, it will take 20 seconds for the ball to travel a distance of 10 m.
Answer:
The correct answer is 231 Mpa i.e option a.
Explanation:
using the equation of torsion we Have
where,
= shear stress at a distance 'r' from the center
T = is the applied torque
= polar moment of inertia of the section
r = radial distance from the center
Thus we can see that if a point is located at center i.e r = 0 there will be no shearing stresses at the center due to torque.
We know that in case of a circular section the maximum shearing stresses due to a shear force occurs at the center and equals
Applying values we get
