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Fynjy0 [20]
3 years ago
7

1 6. Which of the following astronomical units is c/osest to the distance of the earth to the sun?

Physics
1 answer:
Ganezh [65]3 years ago
6 0

Answer:

astronomical unit

Explanation:

https://en.wikipedia.org/wiki/Astronomical_unit

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love history [14]

Answer:

The correct answer is 24.

Explanation:

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3 years ago
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A series circuit has a capacitor of 0.25 × 10−6 F, a resistor of 5 × 103 Ω, and an inductor of 1 H. The initial charge on the ca
svetoff [14.1K]

Answer:

q=10^{-6}(e^{-4000t}-4e^{-1000t}+3)C

Explanation:

Given that L=1H, R=5000\Omega, \ C=0.25\times10^{-6}F, \ \ E(t)=12V, we use Kirchhoff's 2nd Law to determine the sum of voltage drop as:

E(t)=\sum{Voltage \ Drop}\\\\L\frac{d^2q}{dt^2}+R\frac{dq}{dt}+\frac{1}{C}q=E(t)\\\\\\\frac{d^2q}{dt^2}+5000\frac{dq}{dt}+\frac{1}{0.25\times10^{-6}}q=12\\\\\frac{d^2q}{dt^2}+5000\frac{dq}{dt}+4000000q=12\\\\m^2+5000m+4000000=0\\\\(m+4000)(m+1000)=0\\\\m=-4000  \ or \ m=-1000\\\\q_c=c_1e^{-4000t}+c_2e^{-1000t}

#To find the particular solution:

Q(t)=A,\ Q\prime(t)=0,Q\prime \prime(t)=0\\\\0+0+4000000A=12\\\\A=3\times10^{-6}\\\\Q(t)=3\times10^{-6},\\\\q=q_c+Q(t)\\\\q=c_1e^{-4000t}+c_2e^{-1000t}+3\times10^{-6}\\\\q\prime=-4000c_1e^{-4000t}-1000c_2e^{-1000t}\\q\prime(0)=0\\\\-4000c_1-1000c_2=0\\c_1+c_2+3\times10^{-6}=0\\\\#solving \ simultaneously\\\\c_1=10^{-6},c_2=-4\times10^{-6}\\\\q=10^{-6}e^{-4000t}-4\times10^{-6}e^{-1000t}+3\times10^{-6}\\\\q=10^{-6}(e^{-4000t}-4e^{-1000t}+3)C

Hence the charge at any time, t is q=10^{-6}(e^{-4000t}-4e^{-1000t}+3)C

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3 years ago
The graph in the figure shows the variation of the electric potential V(x) (in arbitrary units) as a function of the position x
dmitriy555 [2]
The best and most correct answer among the choices provided by your question is the second choice or letter b.

Ex is negative from x = -2 to x = 0, and positive from x = 0 to x = 2 <span>correctly describes the orientation of the x-component of the electric field along the x-axis.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Use newton's third law to explain why a blown up balloon but untied balloon will fly around the room when you let it go? really
den301095 [7]
Newton's third law of motion states that for every action there is an equal and opposite reaction. The balloon travels in the opposite direction as the air escaping from it. So when gas is released from the balloon it pushes against the outside air and the outside air pushes back. As a result of this the rocket is propelled forward by the opposing force. This opposing force is thrust. 

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3 years ago
A person sitting on a pier observes incoming waves that have a sinusoidal form with a distance of 2.5 m between the crests. Of a
Doss [256]

Answer:

Part(a): The frequency is \bf{0.2~Hz}.

Part(b): The speed of the wave is \bf{0.5~m/s}.

Explanation:

Given:

The distance between the crests of the wave, d = 2.5~m.

The time required for the wave to laps against the pier, t = 5.0~s

The distance between any two crests of a wave is known as the wavelength of the wave. So the wavelength of the wave is \lambda = 2.5~m.

Also, the time required for the wave for each laps is the time period of oscillation and it is given by T = 5.0~s.

Part(a):

The relation between the frequency and time period is given by

\nu = \dfrac{1}{T}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)

Substituting the value of T in equation (1), we have

\nu &=& \dfrac{1}{5.0~s}\\~~~&=& 0.2~Hz

Part(b):

The relation between the velocity of a wave to its frequency is given by

v = \nu \lambda~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)

Substituting the value of \nu and \lambda in equation (2), we have

v &=& (0.2~Hz)(2.5~m)\\~~~&=& 0.5~m/s

5 0
3 years ago
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