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Tamiku [17]
3 years ago
5

Consider the following scenario. A car for which friction is not negligible accelerates from rest down a hill, running out of ga

soline after a short distance (see below). The driver lets the car coast farther down the hill, then up and over a small crest. He then coasts down that hill into a gas station, where he brakes to a stop and fills the tank with gasoline. Identify the forms of energy the car has, and how they are changed and transferred in this series of events.
Physics
1 answer:
drek231 [11]3 years ago
6 0

Answer:

1) U-> K +W

2) K -> W

Explanation:

In this exercise, care must be taken as they indicate that the friction force (rubbing) is not negligible.

1 part at the top of the hill the car has gravitational potential energy, which is transformed in a part into kinetic energy and another part into heat by the work of the friction force that opposes the movement.

2 part when the other hill rises it loses kinetic energy that is transformed into gravitational potential energy and part in heat due to the work of the friction force on this hill.

3rd part in the last descent all the gravitational potential energy is transformed into kinetic energy and the application of the brakes is transformed into heat due to the negative lock of the friction force and filled with gasoline that has chemical energy that can be transformed in the engine.

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Can there be any heat transfer between two bodies that are at the same temperature but at different pressures?
Alenkinab [10]

Answer:

No

Explanation:

When the two bodies at different temperatures then heat transfer takes place between two bodies. Temperature is the necessary condition for the heat transfer.

The energy can flow due to pressure difference but the heat transfer can not take place only due to pressure difference. Heat transfer needs temperature difference.

Therefore the answer will be No.

3 0
3 years ago
What does it mean to say that the average speed of a car is 35 miles per hour?
LenKa [72]
It means that the car has covered

(35 miles) x (the number of hours since it started traveling).

At some points during that time, the car was most likely moving
faster or slower than 35 miles per hour.  We don't know.  We only
know that it covered  (35 miles) x (the number of hours since it left).
6 0
3 years ago
A future use of space stations may be to provide hospitals for severely burned persons. It is very painful for a badly burned pe
inessss [21]

Answer:

1.5min

Explanation:

To solve the problem it is necessary to take into account the concepts related to Period and Centripetal Acceleration.

By definition centripetal acceleration is given by

a_c = \frac{V^2}{r}

Where,

V = Tangencial velocity

r = radius

With our values we know that

a_c = \frac{V^2}{r}

\frac{V^2}{r} = \frac{1}{10}g

Therefore solving to find V, we have:

V = \sqrt{\frac{1}{10}g*r}

V = \sqrt{\frac{9.81*200}{10}}

V = 14m/s

For definition we know that the Time to complete are revolution is given by

t = \frac{Perimeter}{Speed}

t = \frac{2\pi R}{V}

t = \frac{2\pi * 200}{14}

t = 1.5min

6 0
3 years ago
a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what i
Katyanochek1 [597]
Part A: 
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
             a = (Vf - Vi) / t
where a is acceleration,
Vf is final velocity,
Vi is initial velocity, and
t is time

Substituting,
            a = (9 m/s - 0 m/s) / 3 s = 3 m/s²
<em>ANSWER: 3 m/s²</em>

Part B: 
From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,
               F = m x a
where F is force,
m is mass, and 
a is acceleration

Substituting,
              F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N

<em>ANSWER: 240 N </em>

Part C: 
The distance that the sprinter travel is calculated through the equation,
         d = V₀t + 0.5at²

Substituting,
            d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
             d = 13.5 m

<em>ANSWER: d = 13.5 m</em>

3 0
3 years ago
If everything with mass is attracted to every other thing with mass, why doesn’t all the matter in the universe pull together in
kupik [55]

Answer:

i need more info

Explanation:

6 0
3 years ago
Read 2 more answers
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