Find the magnitude of the force that our planet's magnetic field exerts on this wire if it is oriented so that the current in it
1 answer:
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Answer:
y = 10.2 m
Explanation:
It is given that,
Charge,
It is placed at a distance of 9 cm at x axis
Charge,
It is placed at a distance of 16 cm at x axis
We need to find the point on the y-axis where the electric potential zero. The net potential on y-axis is equal to 0. So,
Here,
So,
Squaring both sides,
So, at a distance of 10.2 m on the y axis the electric potential equals 0.
The universal law of gravitation states that:
Every object in the universe attracts every other object with a force which is proportional to the product of their masses and inversely proportional to the square of distance between them.
It means that if the gravitational force is F, then if the distance is decreased by 5 times, then the new gravitation force is:
F/5² = F/25
