The area under the curve of the net external force vs time graph is equal to __________ or _______

The mechanism for the given reaction by adding the missing bonds, charges, nonbonding electrons, and curved arrows is as represented in the attached image.

<h3>Mechanism of Organic Reactions</h3>

The representation of an organic reaction mechanism typically includes designation of the overall reaction type (which may be substitution, addition, elimination, oxidation, reduction, or rearrangement), the presence of any reactive intermediates, the nature of the reagent that initiates the reaction, the presence of any catalysis as facilitated by a catalyst, and ultimately it's stereochemistry.

Read more on mechanism of Organic Reactions;

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2 years ago

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The energy of an onject as it is in motion is defined as?

Ivan

The energy of an object as it is in motion is defined as Kinetic energy.

<u>Explanation:</u>

The energy that is attained by an object when it is moving is called as Kinetic energy. It is the amount of energy that is essential for inducing an acceleration in an object and making it to displace from its idle position to the destination. When an object attains the acceleration it can have this kinetic energy until there is a change in the speed of the object with which it moves.

The forms of energy changes and it can take any form like thermal, electrical, electromagnetic,etc. Potential and kinetic energy are the two things under which these forms are energy are grouped. There can be a transferring of Kinetic energy from one object to another. The kinetic energy can also take any form of energy.

7 0

3 years ago

The angular acceleration of a wheel is given in rad/s2 by 32 t 3 - 11t 4, where t is in seconds. if the wheel starts from rest a

disa [49]

Answer:

$t=3.64s$

Step by step explanation

Step 1

In this step we use the definition of acceleration to determine the expression to integrate. Note that the acceleration is the derivative of velocity with respect to time.

$a=\frac{dv}{dt} \\\implies adt=dv\\\implies dv=(32t^3-11t^4)dt$

Step 2

Perform integration on the expression from step 1. This calculation is performed as shown below.

$v=\int(32t^3-11t^4)dt\\v=\frac{32}{4}t^4- \frac{11}{5}t^5 +c\\\8t^4- \frac{11}{5}t^5 +c$

Step 3

In this step we use the condition that at $t=0$ , the velocity $v=0$ to find the exact form of the velocity function. We substitute this point into the velocity function we found in step 2.

$0=8(0)^4-\frac{11}{5} (0)^5+c\\\implies c=0$

Step 4

We now use the function in step 3 to find out when the velocity is zero again.

$v=0=8t^5-\frac{11}{5}t^4\\\implies 0=8t^4-\frac{11}{5} t^5\\\implies t^4(8-\frac{11}{5} t)\\\implies t=0, 8-\frac{11}{5}t=0\\\\\implies t=0,t=\frac{40}{11} =3.64$

The velocity is zero again when $t=3.64$

8 0

3 years ago

The area under the curve of the net external force vs time graph is equal to __________ or ________.

The area under the curve of the net external force vs time graph is equal to __ or .