The acceleration of the ball is 5 m/s^2. This can be calculated using a formula that relates the change in velocity, acceleration, and time. This formula is:
Vf = Vi + at
where:
Vf = final velocity
Vi = initial velocity
a = acceleration
t = time
Substituting the values gives:
30 = 20 + a(2)
<span>a = 5 m/s^2 --> Final Answer</span>
Answer:
Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.
Explanation:
this is what i know but i am sorry if this doesn't help
<h3>
Answer:</h3>
35 meters
<h3>
Explanation:</h3>
<u>Data given;</u>
- Velocity of an object = 5 m/s
- Time taken = 7 s
We are required to calculate how far the object traveled.
Velocity = Displacement ÷ time
Displacement = Velocity × time
= 5 m/s × 7 s
= 35 m
Therefore; the object traveled 35 meters
Answer:
A.) 27000 kgm/s
18000 kgm/s
B.) Va = 22 m/s
C.) 19800 kgm/s
25200 kgm/s
Explanation: Given that the velocity of A and B are 30 m/s and 20 m/s. And of the same mass M = 9 × 10^5g
M = 9×10^5/1000 = 900 kg
A.) Initial momentum of A
Mu = 900 × 30 = 27000 kgm/s
Initial momentum of B
Mu = 900 × 20 = 18000 kgm/s
B.) if they have an accident and then the velocity of the B is 28 m/s, find out velocity of A.
Momentum before impact = momentum after impact
Given that Vb = 28 m/s
27000 + 18000 = 900Va + 900 × 28
45000 = 900Va + 25200
900Va = 45000 - 25200
900Va = 19800
Va = 19800/900
Va = 22 m/s
C.) Momentum of A after impact
MV = 900 × 22 = 19800 kgm/s
Momentum of B after impact
MV = 900 × 28 = 25200 kgm/s
Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As we know that initially the grass hopper is at rest at the ground position
Now the acceleration is given as
distance of the legs that it stretched is given as
so we have
Part b)
time taken to reach this speed is given as
Part c)
as the grass hopper reach the maximum height its final speed would be zero
so we will have