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3 years ago

5

A ball is thrown horizontally from a 19 m -high building with a speed of 2.0 m/s . How far from the base of the building does th

e ball hit the ground?

1 answer:

bazaltina [42]3 years ago

3 0

Using the formula: ΔY = V₀y * t + (1/2) * ay * t²

Solve for time and get: 1.968s

Then use: v = d/t in the x-direction and get: d = 3.936

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500cm3 of water is to be jeated from room temperature 28oc to 100oc in order to prepare ahot cup pf coffee. What os the minimum

klasskru [66]

Answer:

The minimum heat required is 171626 joules.

Explanation:

By First Law of Thermodynamics, the amount of heat ( $Q$ ), in joules, is equal to the change in internal energy of water. The minimum heat required is the sensible heat necessary to heat up the water. That is:

$Q = \rho\cdot V \cdot c\cdot \Delta T$ (1)

Where:

$\rho$ - Density of water, in kilograms per cubic meter.

$V$ - Volume of water, in cubic meters.

$c$ - Specific heat of water, in joules per kilogram-degree Celsius.

$\Delta T$ - Change in temperature, in degrees Celsius.

If we know that $\rho = 1000\,\frac{kg}{m^{3}}$ , $V = 5\times 10^{-4}\,m^{3}$ , $c = 4186\,\frac{J}{kg\cdot ^{\circ}C}$ and $\Delta T = 82\,^{\circ}C$ , then the minimum heat required is:

$Q = 171626\,J$

The minimum heat required is 171626 joules.

7 0

3 years ago

A student drove to the university from her home and noted that the odometer on her car increased by 16.0 km. The trip took 19.0

777dan777 [17]

ANSWER:

a. 50.53 km/h

b. 32.53 km/h (in the direction of 25˚ S of E)

c. 4.27 km/h

d. 0 km/h

STEP-BY-STEP EXPLANATION:

a.

We have that the speed is given by the following formula:

$\begin{gathered} s=\frac{d}{t} \\ \text{ where s is the speed, d is the distance and t is the time} \end{gathered}$

We know that the equivalence between minutes and hours is that 60 minutes equals 1 hour, therefore:

$s=\frac{16\text{ km}}{19\text{ }\min\frac{1\text{ h}}{60\text{ min}}}=50.53\text{ km/h}$

b.

The velocity is given by the following formula

$\begin{gathered} v=\frac{\Delta x}{t} \\ \text{replacing:} \\ v=\frac{10.3\text{ km-}0\text{ km}}{19\text{ }\min \frac{1\text{ h}}{60\text{ min}}}=32.53 \end{gathered}$

c.

The total distance traveled would then be two 16 kilometers, that is 32 km and the time would be 7.5 hours. we replace

$s=\frac{32\text{ km}}{7.5\text{ h}}=4.27\text{ km/h}$

d.

Since it starts in the same place that it ends, the displacement is equal to 0, therefore, the velocity is equal to 0 km/h

5 0

2 years ago

Two small balls, each of mass 5.0 g, are attached to silk threads 50 cm long, which are in turn tied to the same point on the ce

Rama09 [41]

In triangle ABC

Sin5 = BC/AC

BC = (AC) Sin5

BC = (50) Sin5 = 4.36 cm

r = distance between the two balls = 2 BC = 2 x 4.36 = 8.72 cm = 0.0872 m

q = charge on each ball

m = mass of each ball = 5 g = 0.005 kg

electric force between the two balls is given as

F = $\frac{kq^{2}}{r^{2}}$

using equilibrium of force in vertical direction

T Cos5 = mg eq-2

Using equilibrium of force in horizontal direction

T Sin5 = F eq-3

dividing eq-3 by eq-2

T Sin5 /(T Cos5) = F/mg

F = mg tan5

using eq-1

$\frac{kq^{2}}{r^{2}}$ = mg tan5

inserting the values

$\frac{(9 \times 10^{9})q^{2}}{(0.0872)^{2}}$ = 0.005 x 9.8

q = 2.03 x 10⁻⁷ C

sign of charge is same on both the balls. either it is negative or positive

4 0

3 years ago

A 0.086 kg bullet is fired at 266 m/s and collides with a 6.3 kg wooden block that is initially stationary. The bullet embeds in

olga2289 [7]

Answer:

The value of speed of wooden block at the instant after the collision $V_f =$ 262.41 $\frac{m}{s}$

Explanation:

Given data

Mass of block = 6.3 kg

Mass of bullet = 0.086 kg

Velocity of bullet $V_0$ = 266 $\frac{m}{s}$

Final velocity of whole system is

$V_f = M_{b}\frac{ V_0}{M_b + (M_{block})}$

Put all the values in above formula we get

$V_f = \frac{(6.3)(266)}{(6.3 + 0.086)}$

$V_f =$ 262.41 $\frac{m}{s}$

This is the value of speed of wooden block at the instant after the collision.

7 0

3 years ago

The position of a particle moving on x-axis is given by x(t)=t^2 + 2, it’s average velocity in the final interval from t=1 to t=

san4es73 [151]

Answer:

The average velocity is 2 m/s.

Explanation:

The velocity of the particle is the time derivative of its position $x(t):$

$v =\frac{dx(t)}{dt} = \frac{d}{dt}[t^2+2]$

$v =2t$

Now the average from $t=1$ and $t=2$ is

$v_{avg} = \dfrac{v(2)-v(1)}{2-1} = \dfrac{2(2)-2(1)}{1}$

$\boxed{v_{avg} = 2 m/s} \text{ ( If the units are m/s)}$

Thus, the average velocity is 2 m/s.

8 0

4 years ago