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3 years ago

What is the weight of an 1000 gram mass

2 answers:

8 0

That depends on where you weigh it.

-- On Earth, it weighs 9.807 newtons (2.205 pounds).

-- On the moon, it weighs 1.623 newtons (5.84 ounces).

-- On Jupiter, it weighs 24.79 newtons (5.57 pounds).

BTW ... 1,000 grams of mass is called ' one kilogram '.

DedPeter [7]3 years ago

5 0

Well first and foremost, we can see that the problem gives us the mass in grams, which is a metric unit. And as such, we will want to solve for the metric unit of weight, the Newton.

In order to solve for weight, one must first realize what weight is. Weight is simply the force that the earth (or any given celestial being the object resides on) is applying to the object, to keep it pulled down. So weight is force.

Newton's second law of motion states that Force is equal to mass times acceleration. Mass is 1,000 grams, but one must keep in mind that a Newton is a kilogram times meter per second^2, so we want to convert our mass to kilograms. 1,000 grams is equal to 1 kilogram. Now we have our mass.

Next is acceleration. As stated earlier, weight is the force that gravity applies on an object, so acceleration must then be the acceleration due to gravity, which we know is 9.8 meters per second^2. Now we just plug in numbers.

F=ma

F=(1 kg)(9.8 m/sec^2)

F=9.8 (kg x m)/sec^2

F=9.8 N

Hence the earth is applying 9.8 Newtons of force on the object due to gravity, so the object weighs <u>9.8 Newtons</u>
Hope this helps :)

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Describe J.J Thomson's plum pudding model,and explain how it compares to the modern day atomic theory.

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The correct answer to this open question is the following.

The J.J Thomson's plum pudding model establishes that when he researched the atom, he found that electrons are positively charged. Because he observed that electrons were embedded like plums. Electrons are negative. However, compared to the modern-day atomic theory, scientist Ernest Rutherford established that the space between an atom is empty, the nucleus of the atom is positive, and negative electrons have fixed motion paths.

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2 years ago

Read 2 more answers

The loop is in a magnetic field 0.20 T whose direction is perpendicular to the plane of the loop. At t = 0, the loop has area A

love history [14]

Answer:

Part a)

$EMF = 14 \times 10^{-3} V$

Part b)

$EMF = 15.67 \times 10^{-3} V$

Explanation:

As we know that magnetic flux through the loop is given as

$\phi = B.A$

now we have

$\phi = B\pi r^2$

now rate of change in flux is given as

$\frac{d\phi}{dt} = B(2\pi r)\frac{dr}{dt}$

now we know that

$A = \pi r^2$

$0.285 = \pi r^2$

$r = 0.30 m$

Now plug in all data

$EMF = (0.20)\times 2\pi\times (0.30) \times (0.037)$

$EMF = 14 \times 10^{-3} V$

Part b)

Now the radius of the loop after t = 1 s

$r_1 = r_0 + \frac{dr}{dt}$

$r_1 = 0.30 + 0.037$

$r_1 = 0.337 m$

Now plug in data in above equation

$EMF = (0.20)\times 2\pi\times (0.337) \times (0.037)$

$EMF = 15.67 \times 10^{-3} V$

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3 years ago

A 120 Ohm resistor is connected in

ser-zykov [4K]

Answer:

I=0.05 Amper

v=9 volts

Explanation:

I=V/R1

l=6/120=0.05Amper

voltage of 180ohm =IR2=0.05×180=9volts

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2 years ago

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Answer:

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