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Rasek [7]
3 years ago
14

An airplane flies for 1.25 hours with a constant speed of 1080 km/hr and then for another 2.5 hours with a constant speed of 984

km/hr. How far (what distance) did it go?
Physics
2 answers:
Makovka662 [10]3 years ago
6 0

Answer:

i think its 3583.2km skskks

sattari [20]3 years ago
6 0

Answer:

840 km/h divided by 60 = 14km/min

3 x 60 = 180

180 + 20 = 200 minutes total

14 x 200 = 2800km

that is a really awkward way of doing it though. really you can just do:

840 x (10/3) = 2800km

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densk [106]
Ethylene glycol is termed as the primary ingredients in antifreeze.
The ethylene glycol molecular formula is C₂H₆O₂.
Molar mass of C₂H₆O₂ is = (2×12) +(6×1) + (216) = 62g/mol
Now that antifreeze by mass is 50%, then there is 1kg of ethylene glycol which is present in 1kg of water.
ΔTf = Kf×m
ΔTf = depression in the freezing point.
= freezing point of water freezing point of the solution
= O°c - Tf
= -Tf
Kf = depression in freezing constant of water = 1.86°C/m
M is the molarity of the solution.
=(mass/molar mass) mass of solvent in kg
=1000g/62 (g/mol) /1kg
=16.13m
If we plug the value we get 
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7 0
3 years ago
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Please help me with this 29 points
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Answer:

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a charge of 30. coulombs passes through a 24-ohm resistor in 6.0 seconds. what is the current through the resistor? (1) 1.3 a (3
DochEvi [55]
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Magnet A has twice the magnetic field strength of magnet B and pulls on magnet B with a force of 100 N. The amount of force that
son4ous [18]

The force exerted by the magnetic in terms of the magnetic field is,

F\propto B

Where B is the magnetic fied strength and F is the force.

Thus, if the magnetic A has twice magnetic field strength than the magnet B,

Then,

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Thus, the force exerted by the magnet B is,

\begin{gathered} F_B\propto B_B \\ F_B\propto\frac{B_A}{2} \\ F_B=\frac{F_A}{2} \\ F_B=\frac{100}{2} \\ F_B=50\text{ N} \end{gathered}

Thus, the force exerted by the magnet B on magnet A is 50 N.

The force exerted by the magnet A exerts on the magnet B is exactly 100 N as given.

Hence, the option B is the correct answer.

3 0
11 months ago
Calculate the kinetic energy in joules of a 1,500 kg car that is moving at a speed of 42 km/h
Rzqust [24]
Data:
KE (Kinetic Energy) = ? (Joule)
m (mass) = 1500 Kg 
v (speed) = 42 Km/h
converting to m/s (42 / 3.6), we have: v (speed) = 11.6 m/s

Formula:
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Solving:
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K_{E} =  \frac{201840}{2}
\boxed{\boxed{K_{E} = 100920\:Joule}}\end{array}}\qquad\quad\checkmark





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