Answer:
A)
0.395 m
B)
2.4 m/s
Explanation:
A)
= mass of the cart = 1.4 kg
= spring constant of the spring = 50 Nm⁻¹
= initial position of spring from equilibrium position = 0.21 m
= initial speed of the cart = 2.0 ms⁻¹
= amplitude of the oscillation = ?
Using conservation of energy
Final spring energy = initial kinetic energy + initial spring energy
B)
= mass of the cart = 1.4 kg
= spring constant of the spring = 50 Nm⁻¹
= amplitude of the oscillation = 0.395 m
= maximum speed at the equilibrium position
Using conservation of energy
Kinetic energy at equilibrium position = maximum spring potential energy at extreme stretch of the spring
Answer:
Explanation:
We can solve the problem by using the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the car in this problem:
u = 0 (it starts from rest)
is the final velocity
s = 10 km = 10 000 m is the displacement
Solving for a, we find:
Is there a multiple choice?
Acceleration= change in speed/ change in time
30-10= 20 (change in speed)
Time= 10 seconds
20/10= 2
Acceleration= 2 m/s^2
Hope this helps! :)
Answer:
B= 3.33 m T
Explanation:
Given that
Speed ,C= 6 x 10⁶ m/s
d= 1 cm = 0.01 m
V= 200 V
The electric field E given as
V= E .d
E=Electric field
d=Distance
V=Voltage
200 = 0.01 x E
E=20000 V/m
The relationship between magnetic and electric field given as
E= C x B
20000 = 6 x 10⁶ x B
B =3333.333 x 10⁻⁶ T
B= 3.33 x 10⁻³ T
B= 3.33 m T
Therefore the magnetic filed will be 3.33 m T.
