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stira [4]
3 years ago
8

A box fails to slide down a ramp at a warehouse. what happens if you put the box on a cart that has wheels?

Physics
2 answers:
My name is Ann [436]3 years ago
5 0

Well the Wheels would help to move the box but you need to have in mind that if the box is heavy you must make sure that it does not role-down because of how heavy the box is.

Explanation:

Wheels would help to move the box down the ramp; yet, if the box is large you must make sure that it does not role-down supporting its own weight.

The ramp on an auto transport truck is handled to lift cars high into the air. An oblique plane makes it easier to raise something heavy, like a rock. Rather of lifting the rock straight up, you can raise it from its initial location with less force by shouldering it up a ramp.


amm18123 years ago
4 0
<span>Well the Wheels would help to move the box but you need to have in mind that if the box is heavy you must make sure that it does not role-down because of how heavy the box is</span>
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A lamp consumes 1000J of ekectrical energy in 10s. Calculate its power.​
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You do 1000 divide it by 10 which equals 100 W
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Question 3. AP PHYSICS. Currently learning about torque so I assume you apply torque. I don't get it at all
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2 years ago
Un cubo de madera de densidad 0.780 g/cm³ mide 11.2 cm en un lado. Cuando se coloca en agua, ¿qué altura del bloque flotará sobr
Stolb23 [73]

Answer:

2.464 cm above the water surface

Explanation:

Recall that for the cube to float, means that the volume of water displaced weights the same as the weight of the block.

We calculate the weight of the block multiplying its density (0.78 gr/cm^3) times its volume (11.2^3  cm^3):

weight of the block = 0.78 * 11.2^3  gr

Now the displaced water will have a volume equal to the base of the cube (11.2 cm^2) times the part of the cube (x) that is under water. Recall as well that the density of water is 1 gr/cm^3.

So the weight of the volume of water displaced is:

weight of water = 1 * 11.2^2 * x

we make both weight expressions equal each other for the floating requirement:

0.78 * 11.2^3 = 11.2^2 * x

then x = 0.78 * 11.2 cm = 8.736 cm

This "x" is the portion of the cube under water. Then to estimate what is left of the cube above water, we subtract it from the cube's height (11.2 cm) as follows:

11.2 cm - 8.736 cm = 2.464 cm

6 0
3 years ago
A soccer ball is rolling past Ramon. He kicks it in the same direction that it IS rolling. What will MOST LIKELY happen?
vovikov84 [41]

<u>Answer:</u>

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6 0
2 years ago
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A cylindrical rod of copper (E = 110 GPa, 16 × 106 psi) having a yield strength of 240 MPa (35,000 psi) is to be subjected to a
Fynjy0 [20]

Answer:

d= 7.32 mm

Explanation:

Given that

E= 110 GPa

σ = 240 MPa

P= 6640 N

L= 370 mm

ΔL = 0.53

Area A= πr²

We know that  elongation due to load given as

\Delta L=\dfrac{PL}{AE}

A=\dfrac{PL}{\Delta LE}

A=\dfrac{6640\times 370}{0.53\times 110\times 10^3}

A= 42.14 mm²

πr² = 42.14 mm²

r=3.66 mm

diameter ,d= 2r

d= 7.32 mm

4 0
2 years ago
Read 2 more answers
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