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3 years ago

When converted to a household measurement, 9 kilograms is approximately equal to a

Physics

1 answer:

Aleks04 [339]3 years ago

8 0

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

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A runner maintains a constant velocity of +3.0 m/s. Which of the following position-time graphs shows the runnerÍs location from

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<span>3 meters a second.
Every 5 seconds, that runner should run 5*3=15 meters
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3 years ago

A car has a mass of 1.50 x 103 kg. If the force acting on the car is 6.75 10°N to

kolbaska11 [484]

Answer:

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Explanation:

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4 years ago

A 1.65 kg mass stretches a vertical spring 0.260 m If the spring is stretched an additional 0.130 m and released, how long does

Irina-Kira [14]

Answer:

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

Explanation:

We notice that block-spring system depicts a Simple Harmonic Motion, whose equation of motion is:

$y(t) = A\cdot \cos \left(\sqrt{\frac{k}{m} }\cdot t +\phi\right)$ (1)

Where:

$y(t)$ - Position of the mass as a function of time, measured in meters.

$A$ - Amplitude, measured in meters.

$k$ - Spring constant, measured in newtons per meter.

$m$ - Mass of the block, measured in kilograms.

$t$ - Time, measured in seconds.

$\phi$ - Phase, measured in radians.

The spring is now calculated by Hooke's Law, that is:

$k = \frac{m\cdot g}{\Delta y}$ (2)

Where:

$g$ - Gravitational acceleration, measured in meters per square second.

$\Delta y$ - Deformation of the spring due to gravity, measured in meters.

If we know that $m=1.65\,kg$ , $g = 9.807\,\frac{m}{s^{2}}$ and $\Delta y = 0.260\,m$ , then the spring constant is:

$k = \frac{(1.65\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{0.260\,m}$

$k = 62.237\,\frac{N}{m}$

If we know that $A = 0.130\,m$ , $k = 62.237\,\frac{N}{m}$ , $m=1.65\,kg$ , $x(t) = 0\,m$ and $\phi = 0\,rad$ , then (1) is reduced into this form:

$0.130\cdot \cos (6.142\cdot t)=0$ (1)

And now we solve for $t$ . Given that cosine is a periodic function, we are only interested in the least value of $t$ such that mass reaches equilibrium position. Then:

$\cos (6.142\cdot t) = 0$

$6.142\cdot t = \cos^{-1} 0$

$t = \frac{1}{6.142}\cdot \left(\frac{\pi}{2} \right)\,s$

$t \approx 0.255\,s$

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

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3 years ago

If a woman needs an amplification of 1.0 ✕ 105 times the threshold intensity to enable her to hear at all frequencies, what is h

Damm [24]

Answer:

50 dB.

Explanation:

given,

Amplification needed by the woman,I= 1 x 10⁵ I₀

where as I₀ is the threshold frequency

overall hearing loss of the woman= ?

Using the equation of sound intensity level

$\beta(dB) = 10 log(\dfrac{I}{I_0})$

$\beta(dB) = 10 log(\dfrac{1\times 10^5\ I_0}{I_0})$

$\beta(dB) = 10 log(1\times 10^5)$

$\beta(dB) = 50\ dB$

The overall hearing loss of woman is equal to 50 dB.

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4 years ago

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Sergio039 [100]

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Tsunami also travels at very high speed; it can travel for a long period of time at high speed without losing much energy.

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3 years ago