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Jet001 [13]
3 years ago
8

¿Cuántos electrones conforman un enlace doble?

Chemistry
1 answer:
Aleks04 [339]3 years ago
6 0

Answer:

Cada átomo aporta dos electrones al enlace, es decir, se comparten dos pares de electrones entre dos átomos. Un ejemplo es la molécula de Oxígeno (O2).

Explanation:

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lisov135 [29]

Answer:

The Earth is a rotating sphere that orbits the Sun. The axis of rotation of the Earth is at a constant tilt with respect to its orbit around the Sun, thus resulting in the change of seasons. Iron and oxygen make up 65% of the Earth's mass. The Earth also has gravity and magnetic force fields.

7 0
3 years ago
Question 15 of 32
Oksi-84 [34.3K]
A. Lithium (Li) and Iodine (I)


An ionic bond is most often formed between a metal and a non-metal. Bromine and bromine will form a diatomic bond, and carbon and chlorine will form a covalent bond.
7 0
3 years ago
Calculate the solubility of Ca(OH)2 in a 0.469M CaCl2 solution at 31°C, given that the Ksp of Ca(OH)2 is 4.96 x 10-6 at that tem
Ghella [55]

The solubility of Ca(OH)2 in a 0.469M CaCl2 solution at 31°C, at given Ksp of Ca(OH)2 is determined as 1.626 mM.

<h3>Dissociation reaction of Ca(OH)2</h3>

The dissociation reaction of Ca(OH)2 is given as follows;

Ca(OH)₂  ⇄ Ca²⁺  + 2OH⁻¹

                     x           2x

Concentration of Ca²⁺ = 0.469 M

Ksp = [x][2x]²

ksp = (0.469)(2x²)

ksp = 4(0.469)x²

ksp = 1.876x²

4.96 x 10⁻⁶ = 1.876x²

x² = (4.96 x 10⁻⁶)/(1.876)

x² = 2.643 x 10⁻⁶

x = √(2.643 x 10⁻⁶)

x = 1.626 x 10⁻³ M

x = 1.626 mM

Thus, the solubility of Ca(OH)2 in a 0.469M CaCl2 solution at 31°C, at given Ksp of Ca(OH)2 is determined as 1.626 mM.

Learn more about solubility here: brainly.com/question/23946616

#SPJ1

3 0
1 year ago
What doe the elements in these groups have in common? a)alkali metals b) halogens c) noble gases
Tpy6a [65]

Answer:

halogens please mark me s brainelist

4 0
3 years ago
(c) ammonium carbonate + lead nitrate ? Step-by-step solution Step 1 of 3 v Step 2 of 3 v Step 3 of 3 ^ c) The ions formed in so
kenny6666 [7]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium carbonate and lead nitrate is given as:

(NH_4)_2CO_3(aq.)+Pb(NO_3)_2(aq.)\rightarrow PbCO_3(s)+2NH_4NO_3(aq.)

Ionic form of the above equation follows:

2NH_4^+(aq.)+CO_3^{2-}(aq.)+Pb^{2+}(aq.)+2NO_3^-(aq.)\rightarrow PbCO_3(s)+2NH_4^+(aq.)+2NO_3^-(aq.)

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Pb^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow PbCO_3(s)

Hence, the net ionic equation is written above.

3 0
3 years ago
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