Answer:
5.72 s
Explanation:
From Newton's law, F = ma
The East is +ve direction, Hence,
F = +8930 N
m = 2290 kg
a = ?
8930 = 2290 × a
a = 8930/2290 = 3.90 m/s²
So, we will find the time it takes the car to stop using the equations of motion
a = 3.90 m/s²
u = initial velocity of the car = - 22.3 m/s (the velocity is to the west)
v = final velocity of the car = 0 m/s (since the car comes to rest)
t = time taken for the car to come to rest = ?
v = u + at
0 = - 22.3 + (3.90)(t)
3.9t = 22.3
t = 5.72 s
Answer:
Explanation:
As we know that the displacement of the particle from the mean position is 1/5 times of its amplitude
so we have
so now we have
now we have
so the phase other particle in opposite direction is given as
so we have phase difference given as
Ernest Rutherford is the answer you are looking for my friend.
D, 0.140 liters! Hang on a sec and I'll show you a trick I use.
