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NNADVOKAT [17]
4 years ago
8

Question: A net force of 16 N [40° W of N] is caused by two applied forces acting on the same object. These two forces are: A) 1

0 N [W] and 12 N [N] B) 12 N [W] and 10 N [N] C) 14 N [W] and 12 N [N] D) 12 N [W] and 14 N [N] E) 10 N [W] and 14 N [N]
Physics
1 answer:
Kaylis [27]4 years ago
3 0
The answer is C.......
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3 years ago
The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371
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Explanation :

First we have to calculate the heat required by water.

q=m\times c\times (T_2-T_1)

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m = mass of water = 250 g

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T_1 = initial temperature of water = 293.0 K

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Now put all the given values in the above formula, we get:

q=250g\times 4.18J/g.K\times (371.2-293.0)K

q=81719J

Now we have to calculate the enthalpy of combustion of octane.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of octane = ?

q = heat released = -81719 J

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Now put all the given values in the above formula, we get:

\Delta H=\frac{-81719J}{0.015mole}

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3 years ago
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3 years ago
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Naddik [55]

Answer:

This question is incomplete, a possible question would be to calculate the work done by the ball.

Work done = 8J

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