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inn [45]
3 years ago
10

A ball is thrown vertically upward with a speed of 12.0 m/s. ( a. How high does it rise?

Physics
1 answer:
sdas [7]3 years ago
5 0
It rises till all of its Kinetic energy is converted into potential energy.

so, mgh=(1/2)m(v^2)

so, h=(v^2)/2g = 12*12/(2*9.81)=7.34 m
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A block of lead has dimensions of 4.50cm by 5.20cm by 6.00cm. The block weighs 1587g. From this information, calculate the densi
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Density = Mass / Volume
Volume = Area x Length = (4.50 x 5.20) x 6.00 = 140.4
Density = 1587 x 140.4 = 222,814.8 g/cm3 (cubed)
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2 years ago
AYUDA!!!!!
ZanzabumX [31]

Answer:

a) El valor de la densidad es 0.79 \frac{g}{cm^{3} } o 790 \frac{g}{cm^{3} }

b) El peso especifico es 7749.9\frac{N}{m^{3} }

Explanation:

a) La densidad se define como la propiedad que tiene la materia, ya sean sólidos, líquidos o gases, para comprimirse en un espacio determinado. En otras palabras, la densidad es una magnitud que permite medir la cantidad de masa que hay en determinado volumen de una sustancia. Entonces, la expresión para el cálculo de la densidad es el cociente entre la masa de un cuerpo y el volumen que ocupa:

d=\frac{m}{V}

En este caso:

  • masa= 237 g= 0,237 kg (siendo 1000 g= 1 kg)
  • volumen= 300 cm³= 0,0003 m³ (siendo 1 cm³= 0,000001 m³)

Reemplazando:

d=\frac{237 g}{300cm^{3} } →  d=0.79 \frac{g}{cm^{3} }

d=\frac{0,237 kg}{0,0003m^{3} }→  d=790 \frac{g}{cm^{3} }

<u><em>El valor de la densidad es 0.79 </em></u>\frac{g}{cm^{3} }<u><em> o 790 </em></u>\frac{g}{cm^{3} }<u><em></em></u>

b) El peso específico es la relación existente entre el peso y el volumen que ocupa una sustancia en el espacio.

Entonces, en este caso, siendo el peso:

P= m*g= 0,237 kg* 9,81 \frac{m}{s^{2} }= 2,32497 N

el peso especifico es calculado como:

Pe=\frac{Peso}{Volumen}= \frac{2,32497N}{0,0003 m^{3} }

Pe= 7749.9\frac{N}{m^{3} }

<u><em>El peso especifico es 7749.9</em></u>\frac{N}{m^{3} }<u><em></em></u>

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