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weqwewe [10]
3 years ago
8

Equation to paragraph plzz

Chemistry
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

AgNO₃₍aq₎₎ + NaCl ₍aq₎₎ --------> NaNO₃₍aq₎ + AgCl₍s₎

Explanation:

Silver Nitrate: AgNO₃

Sodium Chloride: NaCl

Sodium Nitrate: NaNo₃

silver(I) chloride: AgCl

Equation:

AgNO₃₍aq₎₎ + NaCl ₍aq₎₎ --------> NaNO₃₍aq₎ + AgCl₍s₎

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Whoever can answer this I will give all of my points to and brainliest award.
ZanzabumX [31]

i dont see the picture.

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3 years ago
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The bonds of the product store 27 KJ more energy than the bonds of the reactants how is energy conserved during this reaction
Blababa [14]

If the bonds of the product store 27 KJ more energy than the bonds of the reactants, It means the surroundings absorb 27 kj of energy from the reaction system Hence, Option (D) is the correct answer

<h3>What is the Exothermic reaction ?</h3>

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise.

The bonds of the product store 27 KJ more energy than the bonds of the reactants, It means that energy has been absorbed by the surrounding as the product formed is more stable due to more stronger bond

This can be inferred from more stored energy with in the bonds and Thus, It is a exothermic reaction.Hence, Option (D) is the correct answer

Learn more about exothermic reaction here ;

brainly.com/question/9799465

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6 0
2 years ago
How do you solve for the Atomic Mass in chemistry?
loris [4]
Https://www.google.com/search?q=how+to+solve+fir+atomic+mass+in+chemisty&ie=UTF-8&oe=UTF-8&hl=en-us&client=safari#kpvalbx=1
Here is the link to a great video that explains your question nicely, hope this helps.
6 0
4 years ago
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Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
yulyashka [42]

<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

3 0
3 years ago
How do I prepare for my general chemistry labs? How do I get good grades on labs?
Masja [62]
Well you should study how different chemicals work, and make flashcards to carry around or make notes during class to study for later
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4 years ago
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