KE=1/2 m v^2
KE= .5 x 2kg x 15m/s to the 2nd power
KE=225 km/s
Answer:
0.29 m
Explanation:
9 mm = 0.009 m in diameter
Cross-sectional area 
Let the tensile modulus of Nickel
.
The elongation of the rod can be calculated using the following formula:

Larger stars have a higher amount of fuel in order to keep the process of nuclear fusion going.
Given :
A box weighing 12,000 N is parked on a 36° slope.
To Find :
What will be the component of the weight parallel to the plane that balances friction.
Solution :
The component of that will be parallel to the plane to balance friction is :

Therefore, component of force to balance friction is F sin 36° .
Hence, this is the required solution.
A motorcycle speeding up on the highway because kinetic involve movement