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3 years ago

10

A bag contains red, yellow and green sweets.2/5 of the sweets are red and 1/4 of the sweets are yellow. What fraction of the swe

ets are green?

1 answer:

Sauron [17]3 years ago

3 0

Answer:

Let x = the number or green sweets

Let x + 8 = the number of red sweets

red/green: (x + 8)/x = 5/3 Cross multiply

5x = 3(x + 8)

5x = 3x + 24

2x = 24

x = 12 green sweets

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An event has a probability of 2/7. How would you best describe the likelihood of this event? (Hint: Change it to a decimal)

AVprozaik [17]

Answer:

Less Likely

Step-by-step explanation:

A 2/7 probability means that it will happen less than half the time.

The eliminates equally likely, more likely, and certain as those are 50% or greater.

The probability is also greater than 0%, so it's not "impossible"

Therefore, the answer must be B, Less Likely.

It happens less than half the time, but can at times happen.

Hope this helps!

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1 year ago

Read 2 more answers

Mat 540 week 6 homework

Aleks04 [339]

What is the question?

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3 years ago

Please solve these equations much appreciated

Reptile [31]

Answer:

Part c) $V=16,500\ m^3$

Part d) $V=93,312\pi\ mm^3$ or $V=292,999.68\ mm^3$

Step-by-step explanation:

Part c) Find the volume of the inverted rectangular pyramid

The volume of the rectangular pyramid is equal to

$V=\frac{1}{3}Bh$

where

B is the area of the rectangular base

h is the height of pyramid

<em>Find the area of the base B</em>

$B=(60)(15)=900\ m^2$

$h=55\ m$

substitute

$V=\frac{1}{3}(900)(55)$

$V=16,500\ m^3$

Part d) Find the maximum volume of tea in the tea cup

we know that

The volume of cylinder (tea cup) is equal to

$V=\pi r^{2}h$

we have

$r=36\ mm\\h=72\ mm$

substitute

$V=\pi (36)^{2}(72)$

$V=93,312\pi\ mm^3$ -----> exact value

<em>Find the approximate value</em>

assume

$\pi =3.14$

$V=93,312(3.14)=292,999.68\ mm^3$

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2 years ago

What is the amplitude, period, and phase shift of y= 5cos( x/2 + 2pi/3)

nordsb [41]

Y = A cos(Bx + C)
A - amplitude
$\frac{2\pi}{B}$ - period
$- \frac{C}{B}$ - phase shift

$y=5\cos{( \frac{x}{2} + \frac{2\pi}{3} )}
\\
\\y=5\cos{( \frac{1}{2}x + \frac{2\pi}{3})}
\\
\\A=5,B= \frac{1}{2},C= \frac{2\pi}{3}$

Amplitude: 5
Period: $\frac{2\pi}{B}=\frac{2\pi}{\frac{1}{2}}=4\pi$
Phase shift: $- \frac{C}{B} =- \frac{\frac{2\pi}{3}}{\frac{1}{2}}= -\frac{4\pi}{3}$

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2 years ago

Tony had 2/3 of a pound of strawberries. Tony let his friend Larry eat 3/8 of the strawberries. How many pounds of strawberries

NARA [144]

Answer:

B) 1/4

Step-by-step explanation:

2/3lb of Strawberries. His friend at 3/8 of them so that would be 3/8 * 2/3 = 6/24 = 1/4. He ate 1/4lb of the strawberries

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3 years ago