Answer:
0.14917
Step-by-step explanation:
We have been given that adults have IQ scores that are normally distributed with a mean of 95.6 and a standard deviation of 19.5. We are asked to find the probability that a randomly selected adult has an IQ greater than 115.9.
First of all, we will find z-score corresponding to 115.9 using z-score formula.
, where
z = z-score,
x = Random sample score,
= Mean,
= Standard deviation.
Upon substituting our given values in z-score formula, we will get:



Now, we will use normal distribution table to find the
.
Using formula
, we will get:



Therefore, the probability that a randomly selected adult has an IQ greater than 115.9 is 0.14917 or approximately 14.92%.
Answer:
n=16
Step-by-step explanation:
Make an equation
Three times a number minus 9–> 3n-9
Times means multiply, and minus means subtract
Equals two times the number plus 7–> =2n+7
Times means multiply, and plus means add
3n-9=2n+7
Solve for n, by getting n by itself
Subtract 2n from both sides
3n-2n-9=2n-2n+7
n-9=7
Add 9 to both sides
n-9+9=7+9
n=16
Move the decimal place over so you get the decimal point in front of the first number (in this case its 3)
so its 3.543 x 10²
Answer:
9
Step-by-step explanation:
radius is half of the diameter
Answer:
option D would be your answer
Step-by-step explanation:
