Using the ideal gas law: PV=nRT
P is pressure; V is volume; n is the amount in moles; R=0.082; T is temperature in K.
(4.68)*(4.95)=(16.45)*(0.0821)*T
Solve for T.
T=17.15
Answer 1:
Equilibrium constant (K) mathematically expressed as the ratio of the concentration of products to concentration of reactant. In case of gaseous system, partial pressure is used, instead to concentration.
In present case, following reaction is involved:
2NO2 ↔ 2NO + O2
Here, K =
![\frac{[PNO]^2[O2]}{[PNO2]^2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BPNO%5D%5E2%5BO2%5D%7D%7B%5BPNO2%5D%5E2%7D%20)
Given: At equilibrium, <span>PNO2= 0.247 atm, PNO = 0.0022atm, and PO2 = 0.0011 atm
</span>
Hence, K =
![\frac{[0.0022]^2[0.0011]}{[0.247]^2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5B0.0022%5D%5E2%5B0.0011%5D%7D%7B%5B0.247%5D%5E2%7D%20)
= 8.727 X 10^-8
Thus, equilibrium constant of reaction = 8.727 X 10^-8
.......................................................................................................................
Answer 2:
Given: <span>PNO2= 0.192 atm, PNO = 0.021 atm, and PO2 = 0.037 atm.
Therefore, Reaction quotient = </span>
![\frac{[PNO]^2[O2]}{[PNO2]^2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BPNO%5D%5E2%5BO2%5D%7D%7B%5BPNO2%5D%5E2%7D%20)
=
![\frac{[0.021]^2[0.037]}{[0.192]^2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5B0.021%5D%5E2%5B0.037%5D%7D%7B%5B0.192%5D%5E2%7D%20)
= 4.426 X 10^-4.
Here, Reaction quotient > Equilibrium constant.
Hence, <span>the reaction need to go to
reverse direction to reattain equilibrium </span>
Answer:
2.3 L
Explanation:
when you have this eqaution you use P1V1T2=P2V2T1.
since you are looking for volume of gas cylinder that means you are looking for V2.
so you have your given P= 1.0 atm, V=2.5L, T=298K.
They ask you to use STP or standard pressure and temperature.
STP P= 1atm, STP T=273 K
so you are looking for V2 meaning you are going to get V alone so your new equation is P1*V1*TS/ P2* T1= V2
so you now substitue so its now 1*273*2.5/ 1* 298= V
682.5/ 298= V
Lastly V= 2.2902 and you round to tenths so now you have
V= 2.3 L
The term that describes the data that deals with the traits of an object is the term qualitative.
<h3>What is qualitative data?</h3>
The term qualitative data refers to data that is collected from findings that are carried out. It gives the idea of the individual parts of the data that is collected and how it can be accurately used.
It may be pertinent to add that the term "qualitative" come from the word "quality" which has to do with the way in which a thing is or is thought to be. This term is often of very much important when we are dealing with the classification and presentation of data.
Thus the term that describes the data that deals with the traits of an object is the term qualitative.
Learn more about qualitative:brainly.com/question/14265131
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Answer:
The correct option are:
1. (b) current
2. (c) potential
3. (b) coulombs (C)
4. (a) amperes (A)
5. (d) volts (V)
Explanation:
Electric charge is a property of a particle, like electron and proton. The subatomic particles, electrons and protons are negatively and positively charged particles, respectively.
The electric charge of a particle can be measured in <em>coulomb, denoted by C</em>.
Current or electric current is defined as the <em><u>net flow of the electric charges through a given region, per unit time.</u></em> Electric current can be measured in <em>ampere, denoted by A.</em>
<em>Potential or Electric potential</em> is described as the work done to displace the electric charges from one point to another. <em><u>Potential is the driving force for the movement of charges</u></em> and can be calculated in <em>volt, denoted by V.</em>