When light falls on objects, it interacts with them in different ways as shown in the images. What type of interaction is seen i
n each image?
1 answer:
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Data:
KE (Kinetic Energy) = ? (Joule)
m (mass) = 1500 Kg
v (speed) = 42 Km/h
converting to m/s (42 / 3.6), we have: v (speed) = 11.6 m/s
Formula:
Solving:
KE (Kinetic Energy) = ? (Joule)
m (mass) = 1500 Kg
v (speed) = 42 Km/h
converting to m/s (42 / 3.6), we have: v (speed) = 11.6 m/s
Formula:
Solving:
Answer:
The distance between the two slits is 40.11 μm.
Explanation:
Given that,
Frequency
Distance of the screen l = 88.0 cm
Position of the third order y =3.10 cm
We need to calculate the wavelength
Using formula of wavelength
where, c = speed of light
f = frequency
Put the value into the formula
We need to calculate the distance between the two slits
Where, m = number of fringe
d = distance between the two slits
Here,
Put the value into the formula
Hence, The distance between the two slits is 40.11 μm.