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The velocity of the ball when it was caught is 12.52 m/s.
<em>"Your question is not complete it seems to be missing the following, information"</em>,
find the velocity of the ball when it was caught.
The given parameters;
maximum height above the ground reached by the ball, H = 38 m
height above the ground where the ball was caught, h = 30 m
The height traveled by the ball when it was caught is calculated as follows;
y = H - h
y = 38 - 30 = 8 m
The velocity of the ball when it was caught is calculated as;
![v_f^2 = v_0 + 2gh\\\\v_f^2 = 0 + (2\times 9.8 \times 8)\\\\v_f^2 = 156.8\\\\v_f = \sqrt{156.8} \\\\v_f = 12.52 \ m/s](https://tex.z-dn.net/?f=v_f%5E2%20%3D%20v_0%20%2B%202gh%5C%5C%5C%5Cv_f%5E2%20%3D%200%20%2B%20%282%5Ctimes%209.8%20%5Ctimes%208%29%5C%5C%5C%5Cv_f%5E2%20%3D%20156.8%5C%5C%5C%5Cv_f%20%3D%20%5Csqrt%7B156.8%7D%20%5C%5C%5C%5Cv_f%20%3D%2012.52%20%5C%20m%2Fs)
Thus, the velocity of the ball when it was caught is 12.52 m/s.
Learn more here: brainly.com/question/14582703
<span>the ratio of the force produced by a machine to the force applied to it, used in assessing the performance of a machine. I would say the answer is D, but i'm not sure. :)</span>