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PolarNik [594]
3 years ago
11

Quickly spinning the handle of a hand generator, Kristina is able to light three bulbs in a circuit. When she spins the generato

r slowly, the bulbs are very dim. Which statement best explains why the slow generator is not able to power all three light bulbs?
Physics
1 answer:
erastova [34]3 years ago
5 0

Answer:

  • <u><em>Voltage is too low</em></u>

Explanation:

<em>Generators</em> produce a potential difference (voltage) by <em>spinning </em>a coil of wire in a magnetic field by induction.

The  produced voltage is proportional to the relative speed of the coil wire with respect to the magnetic field.

Hence, for a given generator, the higher the speed the higher the potential difference.

Therefore, it is concluded immediately that when Kristina spins the generator slowly, less potential difference (voltage) is generated.

Also, you must know that the brightness of the bulbs varies with the current: the higher the current, the brigther the bulbs.

On the other hand, the basic realtion between voltage (V), resistance (R), and current I) is given by Ohm's law: V = R × I. This is, voltage and current are proportional.

Since the generator is producting less voltage, for the same bulbs (which are resistors) , the current will be lower too. And, as stated, lower current means lower brightness, which explains why when Kristina spins the generator slowly, the bulbs are very dim.

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An artificial satellite is in a circular orbit around a planet of radius r= 2.05 x103 km at a distance d 310.0 km from the plane
lubasha [3.4K]

Answer:

\rho = 12580.7 kg/m^3

Explanation:

As we know that the satellite revolves around the planet then the centripetal force for the satellite is due to gravitational attraction force of the planet

So here we will have

F = \frac{GMm}{(r + h)^2}

here we have

F =\frac {mv^2}{(r+ h)}

\frac{mv^2}{r + h} = \frac{GMm}{(r + h)^2}

here we have

v = \sqrt{\frac{GM}{(r + h)}}

now we can find time period as

T = \frac{2\pi (r + h)}{v}

T = \frac{2\pi (2.05 \times 10^6 + 310 \times 10^3)}{\sqrt{\frac{GM}{(r + h)}}}

1.15 \times 3600 = \frac{2\pi (2.05 \times 10^6 + 310 \times 10^3)}{\sqrt{\frac{(6.67 \times 10^{-11})(M)}{(2.05 \times 10^6 + 310 \times 10^3)}}}

M = 4.54 \times 10^{23} kg

Now the density is given as

\rho = \frac{M}{\frac{4}{3}\pi r^3}

\rho = \frac{4.54 \times 10^{23}}{\frac{4}[3}\pi(2.05 \times 10^6)^3}

\rho = 12580.7 kg/m^3

8 0
2 years ago
A cyclist is traveling 10 m/s with an acceleration of 6 m/s2. How fast is the cyclist traveling at the end of 20 seconds
krok68 [10]

Answer:

<em>The cyclist is traveling at 130 m/s</em>

Explanation:

<u>Constant Acceleration Motion </u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

v_f=v_o+at

The cyclist initially travels at 10 /s and it's accelerating at a=6m/s^2. We need to know the new speed when t= 20 seconds have passed.

Apply the above equation:

v_f=10+6\cdot 20

v_f=10+120

v_f=130\ m/s

The cyclist is traveling at 130 m/s

7 0
3 years ago
Physical Science Essential Question: How can the scientific process be used to help us investigate and understand natural phenom
12345 [234]

Answer:

It C 100% bc i alrweady learn this

6 0
2 years ago
A seafloor plate slides under a continental plate during subduction. which type of plate boundary best describes this situation
Leto [7]

Answer:

The situation where a seafloor plate slides under a continental plate during subduction is best described by convergent plate boundary.

Explanation:

The earth’s crust is broken down into tectonic plates that can move independently. They can interact in three different ways: converge (move toward one another), diverge (move away from one another) or transform (slide past one another). The three kinds of plate margins (boundaries where plates meet) are oceanic-oceanic, continental-continental, and continental-oceanic.

The regions where the plates are moving towards one another are known as convergent plate boundaries. During the convergence of continental and oceanic plates, the more-dense oceanic plate sinks below the less-dense continental plate and the oceanic plate is forced down further into the mantle. This is known as subduction. When the plate enters the mantle, the inside pressure breaks the rock. The broken rocks begins to melt from the heat due to the friction and as a result magma is formed. This magma rises toward the surface by breaking through the crust and forms a chain of volcanoes known as a volcanic arc such as the Cascade Mountains of North America and the Andes Mountains of South America.

During the convergence of two oceanic plates, one of the plates sinks underneath the other and forms an ocean trench (deep depression). The plate that sinks further down into the mantle starts to melt and as a result magma rises toward the surface and forms a chain of volcanic islands behind the ocean trench.

During the convergence of two continental plates, they buckle and compress to form complex mountains ranges of great height such as the Himalayas.

5 0
3 years ago
Determine the mass of a ball with a velocity of 40.0 m/s and a wavelength of 8.92 Ã 10-34 m.
posledela
The wavelength is equal to Planck's constant divided by the ball's momentum.
This means that:
lambda = h / p .............> equation I
Momentum = mass * velocity ............> equation II

Substitute by equation II in equation I, you get:
lambda = h / mv
Now, we are given:
lambda = 8.92 * 10^-34 m
Planck's constant = 6.625 * 10^-34
velocity = 40 m/sec

Substitute with these givens in the above equation to calculate the mass as follows:
8.92*10^-34 = (6.625*10^-34) / (40*m)
mass = 0.0185678 kg

4 0
2 years ago
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