Answer:
Wave A
<em>I</em><em> </em><em>hope this</em><em> </em><em>helps</em><em> </em>
Answer:
the initial velocity is 20 m/s and the acceleration is 2 m/s²
Explanation:
Given equation of motion, v = 20 + 2t
If V represents the final velocity of the object, then the initial velocity and acceleration of the object is calculated as follows;
From first kinematic equation;
v = u + at
where;
v is the final velocity
u is the initial velocity
a is the acceleration
t is time of motion
If we compare (v = u + at) to (v = 20 + 2t)
then, u = 20 and
a = 2
Therefore, the initial velocity is 20 m/s and the acceleration is 2 m/s²
Because if they were in the inside, then they would not be able to sexually reproduct and could not have offspring.
Answer:
An active pendulum has the most kinetic energy at the lowest point of its swing when the weight is moving fastest.
Explanation:
SO YOU HAVE THE LEAST KINETIC ENERGY AT THE HIGHEST POINT OF THE SWING WHEN IT'S NOT ACTIVE
Answer:
The temperature of the steam during the heat rejection process is 42.5°C
Explanation:
Given the data in the question;
the maximum temperature T
in the cycle is twice the minimum absolute temperature T
in the cycle
T = 0.5T
now, we find the efficiency of the Carnot cycle engine
η
= 1 - T/T
η = 1 - T/0.5T
η = 0.5
the efficiency of the Carnot heat engine can be expressed as;
η = 1 - W
/Q
where W is net work done, Q is is the heat supplied
we substitute
0.5 = 60 / Q
Q = 60 / 0.5
Q = 120 kJ
Now, we apply the first law of thermodynamics to the system
W = Q - Q
60 = 120 - Q
Q = 60 kJ
now, the amount of heat rejection per kg of steam is;
q = Q/m
we substitute
q = 60/0.025
q = 2400 kJ/kg
which means for 1 kilogram of conversion of saturated vapor to saturated liquid , it takes 2400 kJ/kg of heat ( enthalpy of vaporization)
q = h
= 2400 kJ/kg
now, at h = 2400 kJ/kg from saturated water tables;
T = 40 + ( 45 - 40 ) ( 
)
T = 40 + (5) × (0.5)
T = 40 + 2.5
T = 42.5°C
Therefore, The temperature of the steam during the heat rejection process is 42.5°C
