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3 years ago

What happens in the gray zone between solid and liquid?-,-

1 answer:

3 0

The gray zone transition is very crucial which includes the inter molecular forces acting on the molecules and each atoms which makes the change in state from hot to cold and cold to hot. and for it to be liquid to solid or solid to liquid the transition needs to cross the gray zone.

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How much heat is needed to raise the temperature of 50.0 g of water by 25.0°C

love history [14]

Answer:

Explanation:

In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as

4.18

∘

Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.

Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of

1 g

of that substance by

∘

In water's case, you need to provide

4.18 J

of heat per gram of water to increase its temperature by

∘

What if you wanted to increase the temperature of

1 g

of water by

∘

? You'd need to provide it with

increase by 1

∘



4.18 J

increase by 1

∘



4.18 J

increase by 2

∘



4.18 J

To increase the temperature of

1 g

of water by

∘

, you'd need to supply it with

increase by 1

∘



4.18 J

increase by 1

∘



4.18 J

...

increase by n

∘



4.18 J

Now let's say that you wanted to cause a

∘

increase in a

2-g

sample of water. You'd need to provide it with

for 1 g of water



4.18 J

for 1 g of water



4.18 J

for 2 g of water



4.18 J

To cause a

∘

increase in the temperature of

grams of water, you'd need to supply it with

for 1 g of water



4.18 J

for 1 g of water



4.18 J

,,,

for m g of water



4.18 J

This means that in order to increase the temperature of

grams of water by

∘

, you need to provide it with

heat

specific heat

This will account for increasing the temperature of the first gram of the sample by

∘

, of the the second gram by

∘

, of the third gram by

∘

, and so on until you reach

grams of water.

And there you have it. The equation that describes all this will thus be

⋅

, where

- heat absorbed

- the mass of the sample

- the specific heat of the substance

- the change in temperature, defined as final temperature minus initial temperature

In your case, you will have

100.0

⋅

4.18

∘

⋅

(

50.0

−

25.0

)

∘

10,450 J

Rounded to three sig figs and expressed in kilojoules, t

Explanation:

3 0

3 years ago

Read 2 more answers

Assume light is traveling through an optical medium of n1 and is incident on a boundary with a different optical medium with n2.

Elza [17]

That n2 = 2*n1. That is, the index of refraction is twice as big in medium 2 since v=c/n

5 0

3 years ago

Part A

geniusboy [140]

Answer:

a) b = -5

b) slope = 3/2

Explanation:

a) The equation of a line is given as y = mx + b, where m is the slope of the line and b is the intercept on the y axis.

Given that y = 3x + b and it passes through the point (2, 1). Hence when x = 2, y = 1. Therefore, substituting for x and y:

1 = 3(2) + b

1 = 6 + b

b = 1 - 6

b = -5

b) The equation of a line passing through two points ( $x_1,y_1$ ) and $x_2,y_2$ is given by:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The equation of the line passing through the two points (0,3) and (4,9) is:

$y-3=\frac{9-3}{4-0}(x-0)\\ \\y-3=\frac{3}{2}x\\ \\y = \frac{3}{2}x+3$

Comparing y = (3/2)x + 3 with y = mx + b, the slope (m) is 3/2

4 0

3 years ago

A trooper is moving due south along the freeway at a speed of 30.1 m/s when a red car passes the trooper. The red car moves with

romanna [79]

Answer:

The correct answer to the following question will be "41.87 m".

Explanation:

The given values are:

The speed of trooper = $30.1 \ m/s$

The velocity of red car = $45.4 \ m/s$

Now,

A red car goes as far as possible until the speed or velocity of the troops is the same as that of of the red car at

$t=\frac{45-30}{2.7}$ (∵ $time=\frac{distance}{time}$ )

$t=5.56 \ sec$

then,

The distance covered by trooper,

$t1=30\times 5.56+\frac{1}{2}\times 2.7\times (5.56)^2$

$=208.33 \ m$

The distance covered by red car,

= $45\times 5.56$

= $250.2 \ m$

Maximum distance = $250.2-208.33$

= $41.87 \ m$

6 0

3 years ago

Ann puts a beaker on the scale which shows the mass to be 1.65kg. The actual mass was 1.72 kg. what was the percent error in Ann

mojhsa [17]

Measured reading is 1.65 kg

actual reading was 1.72 kg

error in the reading is 1.72 - 1.65 = 0.07 kg

Now percentage error is given as

$error = \frac{error}{true reading}*100$

$error = \frac{0.07}{1.72}*100$

$error = 4.1$

<em>so this is -4.1% error as the measured reading is less than the actual value</em>

8 0

3 years ago

What happens in the gray zone between solid and liquid?-,-​

What happens in the gray zone between solid and liquid?-,-