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olganol [36]
2 years ago
8

3 resistors of 3,4 and 12 ohm are there. How would you connect so as to get a resistance more than 5 oh, but less than 7 ohm sho

w using calculations and a diagram
Physics
1 answer:
DochEvi [55]2 years ago
4 0

Answer:

<em>Connecting the 4-ohm and 12-ohm in parallel and followed by the 3-ohm resistor in series. A scheme of the configuration is attached below. Please see the file attached below to know the diagram.</em>

Explanation:

There is the following solution that satisfies all requirements indicated on statement:

<em>Connecting the 4-ohm and 12-ohm in parallel and followed by the 3-ohm resistor in series. A scheme of the configuration is attached below.</em>

R = \frac{(12\,\Omega)\cdot (4\,\Omega)}{12\,\Omega+4\,\Omega}+3\,\Omega

R = 6\,\Omega

Which observes all design requirements.

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the light from andromeda galaxy takes about 2.6 million years to reach earth. which of these statements is correct about the and
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A. it is <span>located at a distance of 2.6 million light years from earth</span>
7 0
3 years ago
Write any two uses of simple machines.
Nana76 [90]
Simple machines could be used to reduce effort or extend the ability of people to perform tasks beyond their normal capabilities.
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2 years ago
A body weighs 100newtons when submerged in water. calculate the upthrust action on the body​
Andrews [41]

Answer:

Upthrust = 20 N

Explanation:

The question says that "A body weighs 100N in air and 80N when submerged in water. Calculate the upthrust acting on the body ?"

Upthrust is defined as the force when a body is submerged in liquid, then liquid applies a force on it.

ATQ,

Weight of body in air is 100 N

Weight of body in water is 80 N

Upthrust is equal to the weight of body in air minus weight of body in water.

Upthrust = 100 N - 80 N

Upthrust = 20 N

So, 20 N of upthrust is acting on the body.

7 0
2 years ago
look at the circuit in the figure. find the current, voltage, and power in each resistor. please list answer
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6 0
2 years ago
The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7
My name is Ann [436]

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

4 0
2 years ago
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