What are the steps used to write ionic formulas for ionic compounds
1 answer:
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It is found that scuba diver’s can safely ascend up to 52.53 ft without Breathing out.
By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling or exhaling then
=patm+
= 101325+ρ
It is given that height is 125ft. Put the value of h in above formula:
h1 =125ft=38.1m
ρ=1.04g/mL=1040kg/
g=9.81
=101325Pa+388711.44
=490036.44Pa
=p atm =101325Pa
It is known that volume and pressure can be expressed as:
V*P=const.
where, V is volume and P is pressure.
Now,
=
=
=490036.44/101325
=4.84
Assume constant temperature
d of seawater = 1.04 g/mL; d of Hg = 13.5 g/mL.
now =p atm+
=490036.44Pa
V*p=const
where, V is volume and P is pressure.
Now,
=
=
=490036.44/X
=490036.44pa/(V2/V1) =326690.96Pa
=patm +p
=101325Pa+ρ
326690.96Pa=101325Pa+ρ
ρgh1 =151987.5-101325=225365.96Pa
ρ=1,04g/mL=1040kg/m3
g=9.81
=225365.96/ρ∗g
=225365.96 / 1040∗9.81
=22.09m= 72.47ft
ΔH=
=125-72.47
=52.53ft
So she can safely ascend up to 52.53 ft without Breathing out
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Answer:
the atomic packing factor of Sn is 0.24
Explanation:
a = b = 5.83A and c = 3.18A.
Volume of unit cell = a²c
= (5.83)² * 3.18 * 10⁻²⁴ cm³
= 1.08 * 10⁻²²cm³
Volume of atoms =
(∴ BCC, effective number of atom is 2)
Volume of atoms =
= 2.55*10⁻²³cm³