Answer:
15.065ft
Explanation:
To solve this problem it is necessary to consider the aerodynamic concepts related to the Drag Force.
By definition the drag force is expressed as:

Where
is the density of the flow
V = Velocity
= Drag coefficient
A = Area
For a Car is defined the drag coefficient as 0.3, while the density of air in normal conditions is 1.21kg/m^3
For second Newton's Law the Force is also defined as,

Equating both equations we have:



Integrating


Here,






Replacing:




Answer:
The pressure must have increased in the process
Explanation:
The State Equation for gasses reads: 
where P is the gas' pressure, V its volume, n the number of moles of gas, R the gas constant and T the temperature in degrees Kelvin.
If the temperature of the gas doesn't change in the described process, the right hand side of the equation stays the same. If that is the case, given that when the Volume of the gas diminishes from 75 liters to 50 liters, then the pressure must have increased to keep that product "P * V" constant:

So the pressure must have gone up to 450 kilopascals.
Answer:
<em>10.90km</em>
Explanation:
Magnitude of the total displacement is expressed using the equation
d = √dx²+dy²
dx is the horizontal component of the displacement
dy is the vertical component of the displacement
dy = -6.7sin27°
dy = -6.7(0.4539)
dy = -3.042
For the horizontal component of the displacement
dx = -4.5 - 6.7cos27
dx = -4.5 -5.9697
dx = -10.4697
Get the magnitude of the bicyclist's total displacement
Recall that: d = √dx²+dy²
d = √(-3.042)²+(-10.4697)²
d = √9.2538+109.6146
d = √118.8684
<em>d = 10.90km</em>
<em>Hence the magnitude of the bicyclist's total displacement is 10.90km</em>
<em></em>
Answer:
10km/h
Explanation:
25÷2.5=10
speed = distance/time
velocity is a magnitude and needs a direction which wasnt provided so its basically the same as the speed